随机播放并仅在PHP foreach循环中显示某个项目

Question

I am trying to get shuffle and only 19 items in a for each loop. I used shuffle() and if (++$i == 19) {break;}, but the problem is one time it returns 12 items, one time 13, and another time 14. What did I do wrong?

Here is the code to check:

<?php
    $i = 0;
    shuffle($children);
    foreach ($children as $child) {
        if ($child['name_total'] > 0) {
            ?>
            <li>
            <?php echo ($child['filter_id'] == 2 ? "<span class='Verified'><i class='fa fa-check-circle'></i></span>" : ""); ?>
                <div class="CatImg"><a title="<?php echo $child['name']; ?>" href="<?php echo $child['href']; ?>"><img alt="<?php echo $child['name']; ?>" src="<?php echo $child['thumb']; ?>"/></a></div>
                <a title="<?php echo $child['name']; ?>" href="<?php echo $child['href']; ?>"><?php echo $child['name']; ?><span class="Total"><?php echo $child['name_total']; ?></span></a>
            </li>
        <?php
        }
        if (++$i == 19) {
            break;
        }
    }
?>

Answer 1

Increase $i only when a result has been printed. Check the value before starting a new foreach loop.

 <?php
$i = 0;
shuffle($children);
foreach ($children as $child) {
    if ($child['name_total'] > 0) {
        ?>
        <li>
        <?php echo ($child['filter_id'] == 2 ? "<span class='Verified'><i class='fa fa-check-circle'></i></span>" : ""); ?>
            <div class="CatImg"><a title="<?php echo $child['name']; ?>" href="<?php echo $child['href']; ?>"><img alt="<?php echo $child['name']; ?>" src="<?php echo $child['thumb']; ?>"/></a></div>
            <a title="<?php echo $child['name']; ?>" href="<?php echo $child['href']; ?>"><?php echo $child['name']; ?><span class="Total"><?php echo $child['name_total']; ?></span></a>
        </li>
    <?php
     $i++;
    }
    if ($i == 19) {
        break;
    }
}
?>