Python扫码枪,用这个代码,每次第一次少最前面一个 数字
787569222258
9787569222258
from pynput import mouse,keyboard
CODE = ""
# 处理键盘输入的数据
def on_release(key):
global CODE
try:
CODE += key.char
except Exception as e:
try:
if key == key.enter: #如果扫码枪中的数据是回车enter按键
if "http" in CODE:
message = CODE.replace("http;","http:")
print(message)
CODE = ""
except Exception as e:
CODE = ""
#监听键盘扫码枪输入
with keyboard.Listener(on_release=on_release) as listener:
listener.join()