doutou19761022 2012-08-21 15:57
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FOREACH在每次迭代时都没有准备PDO语句

I am trying to run a FOREACH with PDO but so far my code seems to iterate only once for the FOREACH and returns only the 1st value.

Here is what I have:

$colors = $_GET['color'];
$colors = explode(' ', $colors);
foreach ($colors as $color) 
    {
    $items = $con -> prepare("SELECT * FROM item_descr WHERE color_base1 = :colorbase1");
    $items -> bindValue(":colorbase1", $color);
    }
$items ->execute();
while($info = $items->fetch(PDO::FETCH_ASSOC)) 
{
echo $info['color_base1'];
}

Note that $colors contains more than 1 different color obtained from checkboxes and a jquery.

Thanks!

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3条回答 默认 最新

  • dpwqicw157673 2012-08-21 16:03
    关注

    Your code is nested wrong: you want to prepare the query once, and execute it multiple times, but you're doing the opposite.

    Rather than:

    foreach ( ... )
    {
        prepare( ... );
        bind( ... );
    }
    execute();
    

    You need:

    prepare( ... );
    foreach ( ... )
    {
        bind( ... );
        $results[] = execute();
    }
    

    Alternatively, you could use an SQL IN clause to build one query rather than having the overhead of going back and forth to the database multiple times.

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