python的struct.unpack函数在Java中如何替代

Question

我测试过ByteBuffer方法,即使参数一致,但是结果并不一致,求解决方法

python:

import struct


def account_id_to_steam_id(account_id: str) -> str:
    first_bytes = int(account_id).to_bytes(4, byteorder="big")

    print(first_bytes)
    last_bytes = 0x1100001.to_bytes(4, byteorder="big")
    print(first_bytes + last_bytes)
    print(struct.unpack(">Q", last_bytes + first_bytes))
    return str(struct.unpack(">Q", last_bytes + first_bytes)[0])


print(account_id_to_steam_id(account_id="1421145735"))

结果: 76561199381411463

java:

    public static byte[] intToByte4(int i) {
        byte[] targets = new byte[4];
        targets[3] = (byte) (i & 0xFF);
        targets[2] = (byte) (i >> 8 & 0xFF);
        targets[1] = (byte) (i >> 16 & 0xFF);
        targets[0] = (byte) (i >> 24 & 0xFF);
        return targets;
    }

main:
    var b1 = NumberUtil.intToByte4(1421145735);
    var b2 = NumberUtil.intToByte4(17825793);
    byte[] result = Arrays.copyOf(b1, b1.length + b2.length);
    System.arraycopy(b2, 0, result, b1.length, b2.length);
    var buffer = ByteBuffer.wrap(result ) //
                               .order(java.nio.ByteOrder.LITTLE_ENDIAN)
    System.out.println(buffer.getLong());

结果: 72075192800031828

Answer 1

Java的字节序可能不同，你把高低字节颠倒一下看看