c语言指针内存分配问题

Question

#include <stdio.h>
#include <stdlib.h>

static char **g_line_info;

static void sip_selected_init(int32_t line_num) {
  const char *temp = locale_info_tr(locale_info(), "Line");
  g_line_info = (char **)malloc(sizeof(char *) * line_num);

  for (int32_t i = 0; i < line_num; i++) {
    char *lin_info = malloc(32);
    snprintf(lin_info, 32, "%s%s%d", temp, " ", i + 1);
    g_line_info[i] = lin_info;
  }
}

static void sip_selected_deinit(int32_t line_num) {
  for (int32_t i = 0; i < line_num; i++) {
    free(g_line_info[i]);
    g_line_info[i] = NULL;
  }
  free(g_line_info);
  g_line_info = NULL;
}

int main() {
  sip_selected_init(1);
  sip_selected_deinit(1);

  // 其他代码...

  return 0;
}

以上代码，为什么不用释放line_info

Answer 1

不是没有释放，只是通过将每次循环创建的line_info字符串地址存放到g_line_info字符串数组内，之后在方法sip_selected_deinit根据字符串数组的下标进行释放line_info字符串