输入读取10高尔夫分数，打印总分平均分差分。把3个for循环合并成1个for循环

Question

#include<stdio.h> 
#define SIZE 10              //10个分数
#define PAR 72              //定义标准分 72
int main(void)
{
    int index,score[SIZE];
    int sum = 0;
    float average;          //平均分
    
    printf("Enter %d golf scores:\n",SIZE);      //输入10个高尔夫分数
    for (index = 0;index < SIZE; index++)
        scanf ("%d",&score[index]);              //读取10个分数
    printf("The score read in are as follows:\n");     //打印输入的分数
    for (index = 0;index < SIZE;index++)
        printf("%5d",score[index]);
    printf("\n");
    
    for (index = 0;index <SIZE ;index ++)
        sum +=score[index];                     //求总分数
    average =(float)sum / SIZE;                  //平均分=总分数除以10
    printf("Sum of scores = %d,average = %.2f\n",sum,average);
    printf("That's a handicap of %.0f.\n",average- PAR);
    return 0;
}

Answer 1

我修改了一下楼下的代码，解决了不能跨行输入的bug
代码如下

#include <stdio.h>
#define SIZE 10
#define PAR 72
int main()
{
    float avgrage;
    int sum = 0;
    int score[SIZE] = {0};
    printf("Enter %d scores:",SIZE);
    for(index = 0;index < 2*SIZE;index++)
    {
        if(index < SIZE)
        {
            scanf("%d",&score[index]);
            getchar();
        }
        else
        {
            if(index == SIZE)
            {
                printf("the score read in are as follows:\n");
            }
            printf("%5d",score[index-SIZE]);
            sum += score[index-SIZE];
        };
    }
    avgrage = sum/(float)SIZE;
    printf("\n");
    printf("Sum of scores: %d,average = %.2f\n",sum,avgrage);
    printf("That's a handicap of:%.0f",avgrage-PAR);
    return 0;
}