php：preg_match：停止搜索文本中是否存在任何模式元素

Question

$pattern = '/^(^[\`\~\@\#\$\%\^\&\\])+$/';
if(preg_match($pattern, $textToSearch)){
   exit('Bad text.');
}

The code above is supposed to exit upon the first occurrence of any element in the pattern above. But it is not working. Will anyone please help me arrive at a working code sample?

Answer 1

Since any occurrence of any of the listed special characters should mark the input as bad, you can make use of the regex: [\`\~\@\#\$\%\^\&\\\\]:

$pattern = '/[\`\~\@\#\$\%\^\&\\\\]/';
if(preg_match($pattern, $textToSearch)){
   exit('Bad text.');
}

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