PHP - 无法显示图像，因为它包含错误

Question

Good day guys,

I inherited some legacy code that reads a BLOB from the database, parses it and returns the jpeg stream to be displayed in the browser. The legacy code used to run on PHP 5.5, it has since been deployed on a PHP 7.1 server where I am running into the issue.

I have made sure that the gd library for php is installed and loaded in Apache, I can verify that it is enabled and working with the php info file. I have also dumped the value from the DB and made sure the blob is a valid image, which it is. For some reason or another I cannot get the function to provide the image.

Here is the code for the function after the data has been retrieved from the DB and stored in $image

$image = imagecreatefromstring($image);

$originalWidth = imagesx($image);
$originalHeight = imagesy($image);

header ( 'Content-type:image/jpeg' );
if($originalWidth == $width && $originalHeight == $height)
{
  if($thumb && $width >= $originalWidth) echo imageautocrop($image);
  else echo imagejpeg($image);
}
else
{
  $ratio = $originalHeight/$originalWidth;

  $height = $width*$ratio;

  $height = round($height);
    $new = imagecreatetruecolor($width, $height);

    imagecopyresampled($new, $image, 0, 0, 0, 0, $width, $height, imagesx($image),imagesy($image));
    imageantialias($new, true);

  if($thumb) imageautocrop($image);
  else imagejpeg($new, null, $quality);

  imagedestroy($new);
} 

I have tried using the exact dimensions as well as the cropped dimensions, neither of which work.