c语言中字符串数组要怎么传参

Question

为什么该段代码各个函数中字符串都不是我输入的结果

#include <stdio.h>
#include <stdlib.h>
int judge1(char (*nums)[5],int i);
int judge2(char (*nums)[5],int i);
int judge3(char (*nums)[5],int i);
int judge4(char (*nums)[5],int i);

int main(int argc, char *argv[])
{
  int i,k,n;
  scanf("%d",&n);
  char **nums=(char**)malloc(n*sizeof(char*));
  int *score=(int*)malloc(n*sizeof(int));
  for(i=0;i<n;i++)
  {
    nums[i]=(char*)malloc(5*sizeof(char));
    score[i]=0;
  }
  for(i=0;i<n;i++)
  {
    scanf("%s",nums[i]);
    score[i]+=judge1(nums,i)+judge2(nums,i)+judge3(nums,i)+judge4(nums,i);
  }
  for(i=0;i<n;i++)
  {
    printf("%d\n",score[i]);
  }
  return 0;
}
int judge1(char (*nums)[5],int i)
{
  printf("函数中nums[i]:%s\n",nums[i]);
  int a=0;
  if(nums[i][0]-nums[i][1]==1&&nums[i][1]-nums[i][2]==1&&nums[i][2]-nums[i][3]==1)
    a+=5;
  if(nums[i][0]-nums[i][1]==-1&&nums[i][1]-nums[i][2]==-1&&nums[i][2]-nums[i][3]==-1)
    a+=5;
  return a;
}
int judge2(char (*nums)[5],int i)
{
  int a=0;
  if(nums[i][0]==nums[i][1]&&nums[i][1]==nums[i][2])
    a+=3;
  if(nums[i][1]==nums[i][2]&&nums[i][2]==nums[i][3])
    a+=3;
  return a;
}
int judge3(char (*nums)[5],int i)
{
  int a=0;
  if(nums[i][0]==nums[i][2]&&nums[i][1]==nums[i][3])
    a+=1;
  if(nums[i][0]==nums[i][1]&&nums[i][2]==nums[i][3])
    a+=1;
  return a;
}
int judge4(char (*nums)[5],int i)
{
  int a=0,k=0;
  for(k=0;k<4;k++)
  {
    if(nums[i][k]==54||nums[i][k]==56||nums[i][k]==57)
      a+=3;
  }
  return a;
  
}

结果如下，通过int judge1(char (*nums)[5],int i);传递参数，但为什么函数中nums[i]这个字符串有问题？

Answer 1

judge函数的参数类型定义二维数组，但是每次调用时只传递一个字符串。

#include <stdio.h>
#include <stdlib.h>

int judge1(char *nums);
int judge2(char *nums);
int judge3(char *nums);
int judge4(char *nums);

int main() {
    int n;
    scanf("%d", &n);

    char **nums = (char**)malloc(n * sizeof(char*));
    int *score = (int*)malloc(n * sizeof(int));

    for (int i = 0; i < n; i++) {
        nums[i] = (char*)malloc(5 * sizeof(char));
        score[i] = 0;
        scanf("%s", nums[i]);
        score[i] += judge1(nums[i]) + judge2(nums[i]) + judge3(nums[i]) + judge4(nums[i]);
    }

    for (int i = 0; i < n; i++) {
        printf("%d\n", score[i]);
    }

    // 释放内存
    for (int i = 0; i < n; i++) {
        free(nums[i]);
    }
    free(nums);
    free(score);

    return 0;
}

int judge1(char *nums) {
    int a = 0;
    printf("函数中nums:%s\n",nums);
    if (nums[0] - nums[1] == 1 && nums[1] - nums[2] == 1 && nums[2] - nums[3] == 1)
        a += 5;
    
    if (nums[0] - nums[1] == -1 && nums[1] - nums[2] == -1 && nums[2] - nums[3] == -1)
        a += 5;
    
    return a;
}

int judge2(char *nums) {
   int a=0;

   if(nums[0]==nums[1]&& nums[1]==nums[2])
       a+=3;

   if(nums[1]==nums[2]&&nums[2]==nums[3])
       a+=3;

   return a;
}

int judge3(char *nums) {
   int a=0;

   if(nums[0]==nums[2]&&nums[1]==nums[3])
       a+=1;

   if(nums[0]==nums[1]&&nums[2]==nums[3])
       a+=1;
   return a;
}

int judge4(char *nums) {
   int a=0,k=0;

   for(k=0;k<4;k++)
   {
       if(nums[k]=='5'||nums[k]=='6'||nums[k]=='7')
           a+=3;
   }

   return a;
}