I tried inserting some license generated kes from a for loop into the database but I was getting Errormessage: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'keys)values('46F2-SH73-2QDD-Z4VH-HV')' at line 1
I have been on it for sometime now trying to fiure it but it gives the same error everytime I run it.
Here is my code:
<?php
//ob_start();
//session_start();
//error_reporting(0);
//ini_set('display_errors', '0');
date_default_timezone_set('Africa/Lagos');
#$db = parse_ini_file("../config/db.ini");
$dbhost = 'localhost'; //$db['host'];
$dbuser = 'root';//$db['user'];
$dbpass = '';//$db['pass'];
$dbname = 'infonetsch_mgmt';//$db['dbname'];
//Connect
$mysqli = new mysqli($dbhost, $dbuser, $dbpass, $dbname);
if (mysqli_connect_errno()) {
printf("MySQLi connection failed: ", mysqli_connect_error());
exit();
}
// Change character set to utf8
if (!$mysqli->set_charset('utf8')) {
printf('Error loading character set utf8: %s
', $mysqli->error);
}
?>
<html>
<head>
<title>License Key Generator</title>
</head>
<body style="background-color:#F0F0F0">
<h1>License Key generation</h1>
<form method="POST" action="">
<table>
<tr>
<td>Keys to generate</td>
<td><select name="numkeys">
<option value="1">1</option>
<option value="5" selected>5</option>
<option value="10">10</option>
<option value="20">20</option>
<option value="50">50</option>
<option value="100">100</option>
<option value="500">500</option>
<option value="1000">1000</option>
<option value="5000">5000</option>
<option value="10000">10000</option>
<option value="20000">20000</option>
<option value="50000">50000</option>
</select></td>
</tr>
<tr>
<td>Length of Key</td>
<td><select name="keylen">
<option value="8">8</option>
<option value="10">10</option>
<option value="12">12</option>
<option value="14">14</option>
<option value="16">16</option>
<option value="18">18</option>
<option value="20">20</option>
</select></td>
</tr>
</table>
<input name="validate" type="submit" value="Generate!"/>
</table>
</form>
<?php
if(isset($_POST['validate'])){
$name= 'a';//$_POST['client'];
$software= 'sis';//$_POST['software'];
$numkeys=$_POST['numkeys']; if($numkeys<1)$numkeys=1; if($numkeys>50000)$numkeys=50000;
$keylen=$_POST['keylen'];if($keylen<1)$keylen=1; if($keylen>20)$keylen=20;
include("license_key.class.php");
$pass=new license_key();
echo "<h3>Generating $numkeys Random License Keys </h3>
KeyLenght: $keylen</a><hr/>";
for($i=0;$i<$numkeys;$i++){
$pass->keylen=$keylen;
$key= $pass->codeGenerate($name.$software);
$get = mysqli_query($mysqli, "insert into license_keys(keys)values('".$key."')");//Insert query
$j=$i+1;
echo "$j- $key <br/>";
}
if($get){
echo "Done";
}else{ printf("Errormessage: %s
", $mysqli->error);; }
echo "<br/><br/><a href=\"test.php\">Generate again</a><br/><br/>";
}
?>
</body>
</html>
Why am I getting such an error?
