dongtang5057 2017-09-27 17:37
浏览 58
已采纳

找到一个用户赞助商无限升级PHP?

Say I have a MySQL table like below. Going from the bottom, I want to find a sponsor that has a "Status = 1". But I want to do it in a order. For e.g. I am "Mike". My sponsor is "Richard". I want to check if "Richard" has a status of 1. He doesn't. So now I am going to check "Richard"'s sponsor to see if he has a status of 1. He doesn't either. So I keep going up, checking my sponsor's sponsor's sponsor...etc.

Normally I can do that with a single or multiple queries if I want to check several levels up. But the problem arises if I want to check infinite levels up until it finds the sponsor who's status is 1? How that work? What would a php query/function look like checking infinite levels up?

    Sponsors     Referrals      Status
    --------------------------------------
    Zack         Joey             1
    Joey         Tracy            0
    Tracy        Helen            0
    Helen        Richard          0
    Richard      Mike             0

</div>
  • 写回答

3条回答 默认 最新

  • doula2426 2017-09-27 18:18
    关注

    Though the solution definitely seems to be to have the parent_id as Lawrence suggests, I though I'd give the PHP solution to this assuming you had the list of people in an array already (i.e., not one query per pair, as that'd be really wasteful).

    What you need to do is recursively iterate through the array, going from sponsor to sponsor until you hit a sponsor with status 1. Take a look at this function:

    <?php
    $people = [
        [
            "sponsor" => "Zack",
            "referal" => "Joey",
            "status" => 1,
        ],
        [
            "sponsor" => "Joey",
            "referal" => "Tracy",
            "status" => 0,
        ],
        [
            "sponsor" => "Tracy",
            "referal" => "Helen",
            "status" => 0,
        ],
        [
            "sponsor" => "Helen",
            "referal" => "Richard",
            "status" => 0,
        ],
        [
            "sponsor" => "Felipe",
            "referal" => "Juan",
            "status" => 0,
        ],
        [
            "sponsor" => "Richard",
            "referal" => "Mike",
            "status" => 0,
        ],
    ];
    static $i = 0;
    function getParentSponsor($referal, $people) {
        foreach ($people as $pair) {
            if ($pair["referal"] === $referal) {
                if ($pair["status"] === 1) { // we found our parent sponsor
                    return $pair["sponsor"];
                }
                else {
                    return getParentSponsor($pair["sponsor"], $people); // we need to go to the next element
                }
                return $pair["sponsor"];
            }
        }
        $i++;
    }
    echo getParentSponsor("Mike", array_reverse($people)).PHP_EOL; // Zack
    echo getParentSponsor("Richard", array_reverse($people)).PHP_EOL; // Zack
    echo getParentSponsor("Joey", array_reverse($people)).PHP_EOL; // Zack
    

    Demo

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
    评论
查看更多回答(2条)

报告相同问题?

悬赏问题

  • ¥100 网页游戏在本地页面修改游戏结果
  • ¥30 comfyui openpose报错
  • ¥20 Wpf Datarid单元格闪烁效果的实现
  • ¥15 图像分割、图像边缘提取
  • ¥15 sqlserver执行存储过程报错
  • ¥100 nuxt、uniapp、ruoyi-vue 相关发布问题
  • ¥15 浮窗和全屏应用同时存在,全屏应用输入法无法弹出
  • ¥100 matlab2009 32位一直初始化
  • ¥15 Expected type 'str | PathLike[str]…… bytes' instead
  • ¥15 三极管电路求解,已知电阻电压和三级关放大倍数