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使用C语言对y86指令进行反汇编

补完三个部分完成的Y86反汇编程序,使得程序能正确完整地完成反汇编功能,反汇编Y86架构中定义的所有指令。
分任务1:能正确反汇编机器操作码。

#include <stdio.h>
#include <stdlib.h>
#include <string.h>

int convertStrToByteCode(const char *str, unsigned char inst[], int size);
void disassembleInstruction(unsigned char instruction[], int size);

int main(int argc, char **argv)
{
  FILE *pFile = NULL;

  char buffer[15];

  if (argc < 2)
  {
    pFile = fopen("./test1.txt", "r");
  }
  else
  {
    pFile = fopen(argv[1], "r");
  }

  if (pFile == NULL)
  {
    printf("Error open test file, please make sure they exist.");

    return 0;
  }

  while (fgets(buffer, 15, pFile) && strlen(buffer) > 1)
  {
    unsigned char instruction[6] = {0, 0, 0, 0, 0, 0};
    convertStrToByteCode(buffer, instruction, 6);

    disassembleInstruction(instruction, 6);
  }

  fclose(pFile);

  return 0;
}

int convertStrToByteCode(const char *str, unsigned char inst[], int size)
{
  int numHexDigits = 0;
  char *endstr;
  numHexDigits = strlen(str) - 1;
  long long value = strtol(str, &endstr, 16);

  int numBytes = numHexDigits >> 1;
  int byteCount = numHexDigits >> 1;

  while (byteCount > 0)
  {
    unsigned long long mask = 0xFF;
    unsigned long shift = (numBytes - byteCount) << 3;

    inst[byteCount - 1] = (value & (mask << shift)) >> shift;
    byteCount--;
  }

  return numHexDigits >> 1;
}

void disassembleInstruction(unsigned char instruction[], int size)
{
  // TODO: Add your implementation here to disassemble the y86 opcodes and display the result.
  // For example, you can use a switch statement or an array of function pointers to handle different opcodes.
  // If an undisassembled opcode is found, display it as "TODO: undisassembled opcode".
}

分任务2:能正确反汇编寄存器操作数。

#include <stdio.h>
#include <stdlib.h>
#include <string.h>

//This is an array of register mnemonics in y86
const char *register_names[] =
    {
        "%eax",
        "%ecx",
        "%edx",
        "%ebx",
        "%esp",
        "%ebp",
        "%esi",
        "%edi",
        "UNKNOWN_REGSITER"};

int convertStrToByteCode(const char *str, unsigned char inst[], int size);

int main(int argc, char **argv)
{
  FILE *pFile = NULL;

  char buffer[15];

  if (argc < 2)
  {
    pFile = fopen("./test1.txt", "r");
  }
  else
  {
    pFile = fopen(argv[1], "r");
  }

  if (pFile == NULL)
  {
    printf("Error open test file, please make sure they exist.\n");

    return 0;
  }

  while (fgets(buffer, 15, pFile) && strlen(buffer) > 1)
  {
    //This unsigned char array stores an instruction read from the file
    //As the largest y86 instruction is 6 bytes, there are 6 unsigned char in the array where
    //each represents a byte.
    unsigned char instruction[6] = {0, 0, 0, 0, 0, 0};
    convertStrToByteCode(buffer, instruction, 6);

    //TODO: From here, your task is to complete the implementation so that all y86 opcode and operands can be disassembled.
    //Any undisassembled opcode should display as "TODO: undisassembled opcode and operands"
    printf("TODO: undisassembled opcode and operands. The first byte of the instruction is 0x%X\n", instruction[0]);
  }

  fclose(pFile);

  return 0;
}

/****************************************************************************
N.B. You do not need to modify or work in this function.
Description:
This function converts a line of machine code read from the text file
into machine byte code.
The machine code is stored in an unsigned char array.
******************************************************************************/
int convertStrToByteCode(const char *str, unsigned char inst[], int size)
{
  int numHexDigits = 0;
  char *endstr;
  //Each instruction should consist of at most 12 hex digits
  numHexDigits = strlen(str) - 1;
  //Convert the string to integer, N.B. this integer is in decimal
  long long value = strtol(str, &endstr, 16);

  int numBytes = numHexDigits >> 1;
  int byteCount = numHexDigits >> 1;

  while (byteCount > 0)
  {
    unsigned long long mask = 0xFF;
    unsigned long shift = (numBytes - byteCount) << 3;

    inst[byteCount - 1] = (value & (mask << shift)) >> shift;
    byteCount--;
  }

  //Return the size of the instruction in bytes
  return numHexDigits >> 1;
}

分任务3:能正确反汇编立即数和存储器地址操作数。


#include <stdio.h>
#include <stdlib.h>

//This is the help function that reads y86 binary code from a file
unsigned int loadBinFromFile(const char *filename, unsigned char memory[], unsigned int memsize);

int main(int argc, char **argv)
{
  unsigned int MAX_MEMSIZE = 4096;
  unsigned char memory[MAX_MEMSIZE]; //This array represents the 4KB memory space
  unsigned int PC = 0;               //This is the initial program counter address

  if (argc < 2)
  {
    printf("Usage: please specify a y86 binary program file in the argument.\n");
    return -1;
  }

  unsigned int program_size = loadBinFromFile(argv[1], memory, MAX_MEMSIZE);

  if (program_size == 0)
    return 0;

  //TODO: Implement your disassembler from here
  //At the moment, it simply display each byte from the memory.
  while (PC < program_size)
  {
    printf("%02X\n", memory[PC]);

    PC++;
  }

  return 0;
}

/****************************************************************************
N.B. You do not need to modify or work in this function.
Description:
This function reads in a y86 machine bytecode from file and
store them in an unsigned char array.
******************************************************************************/
unsigned int loadBinFromFile(const char *filename, unsigned char memory[], unsigned int memsize)
{
  unsigned int bytes_read = 0;

  unsigned int file_size = 0;

  FILE *pfile = fopen(filename, "rb");

  if (!pfile)
  {
    printf("Unable to load file %s, please check if the path and name are correct.\n", filename);
    return 0;
  }

  fseek(pfile, 0, SEEK_END);
  file_size = ftell(pfile);
  rewind(pfile);

  if (file_size > memsize)
  {
    printf("Program size exceeds memory size of %d.\n", memsize);
    return 0;
  }

  bytes_read = fread(memory, 1, file_size, pfile);

  if (bytes_read != file_size)
  {
    printf("Bytes read does not match the file size.\n");
    return 0;
  }

  fclose(pfile);

  return bytes_read;
}
  • 写回答

12条回答 默认 最新

  • 叫兽-郭老师 新星创作者: Java技术领域 2023-12-05 16:21
    关注

    由人工智能和答主提供,可以参考如下,如果回答的不正确,及时评论区回复,我追加回答,谢谢。

    下面是对你的三个任务的中文回答:

    任务1:正确反汇编机器操作码

    #include <stdio.h>
    
    void disassembleInstruction(unsigned char instruction[], int size) {
        unsigned char opcode = instruction[0];
    
        switch (opcode) {
            case 0x00:  // NOP
                printf("nop\n");
                break;
            case 0x10:  // HALT
                printf("halt\n");
                break;
            case 0x20:  // RRMOVL
                printf("rrmovl %s, %s\n", register_names[(instruction[1] >> 4) & 0xF], register_names[instruction[1] & 0xF]);
                break;
            case 0x30:  // IRMOVL
                printf("irmovl $0x%02X%02X%02X%02X, %s\n", instruction[1], instruction[2], instruction[3], instruction[4], register_names[instruction[5] & 0xF]);
                break;
            // 添加更多的指令处理,根据需要
    
            default:
                printf("TODO: 未处理的机器指令\n");
        }
    }
    
    // 其余代码保持不变
    

    任务2:正确反汇编寄存器操作数

    #include <stdio.h>
    #include <stdlib.h>
    #include <string.h>
    
    const char *register_names[] = {
        "%eax",
        "%ecx",
        "%edx",
        "%ebx",
        "%esp",
        "%ebp",
        "%esi",
        "%edi",
        "UNKNOWN_REGSITER"};
    
    // ...(之前的代码保持不变)
    
    void disassembleInstruction(unsigned char instruction[], int size) {
        unsigned char opcode = instruction[0];
    
        switch (opcode) {
            case 0x00:  // NOP
                printf("nop\n");
                break;
            case 0x10:  // HALT
                printf("halt\n");
                break;
            case 0x20:  // RRMOVL
                printf("rrmovl %s, %s\n", register_names[(instruction[1] >> 4) & 0xF], register_names[instruction[1] & 0xF]);
                break;
            case 0x30:  // IRMOVL
                printf("irmovl $0x%02X%02X%02X%02X, %s\n", instruction[1], instruction[2], instruction[3], instruction[4], register_names[instruction[5] & 0xF]);
                break;
            // 添加更多的指令处理,根据需要
    
            default:
                printf("TODO: 未处理的机器指令\n");
        }
    }
    
    // ...(其余代码保持不变)
    

    任务3:正确反汇编立即数和存储器地址操作数

    #include <stdio.h>
    
    // ...(之前的代码保持不变)
    
    void disassembleInstruction(unsigned char instruction[], int size) {
        unsigned char opcode = instruction[0];
    
        switch (opcode) {
            case 0x00:  // NOP
                printf("nop\n");
                break;
            case 0x10:  // HALT
                printf("halt\n");
                break;
            case 0x20:  // RRMOVL
                printf("rrmovl %s, %s\n", register_names[(instruction[1] >> 4) & 0xF], register_names[instruction[1] & 0xF]);
                break;
            case 0x30:  // IRMOVL
                printf("irmovl $0x%02X%02X%02X%02X, %s\n", instruction[1], instruction[2], instruction[3], instruction[4], register_names[instruction[5] & 0xF]);
                break;
            case 0x40:  // RMMOVL
                printf("rmmovl %s, 0x%02X%02X%02X%02X(%s)\n", register_names[(instruction[1] >> 4) & 0xF], instruction[2], instruction[3], instruction[4], instruction[5], register_names[instruction[6] & 0xF]);
                break;
            case 0x50:  // MRMOVL
                printf("mrmovl 0x%02X%02X%02X%02X(%s), %s\n", instruction[2], instruction[3], instruction[4], instruction[5], register_names[instruction[6] & 0xF], register_names[(instruction[1] >> 4) & 0xF]);
                break;
            // 添加更多的指令处理,根据需要
    
            default:
                printf("TODO: 未处理的机器指令\n");
        }
    }
    
    // ...(其余代码保持不变)
    

    这样,你应该能够正确地反汇编Y86架构中定义的常见指令。如果你的Y86指令集包含其他指令,你可能需要扩展代码以支持这些指令。

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问题事件

  • 已结题 (查看结题原因) 12月7日
  • 创建了问题 12月5日