
编写函数f,由实参传来n个字符串,n不超过5,统计这些字符串中字母 数字 空格和其他字符的个数
#include <stdio.h>
int f(char ** a, int n, int * l, int * d, int * s, int * o)
{
*l = *d = *s = *o = 0;
for (int i = 0; i < n; i++)
{
for (int j = 0; a[i][j] != '\0'; j++)
{
if ((a[i][j] >= 'a' && a[i][j] <= 'z') || (a[i][j] >= 'A' && a[i][j] <= 'Z'))
*l += 1;
else if (a[i][j] >= '0' && a[i][j] <= '9')
*d += 1;
else if (a[i][j] == ' ')
*s += 1;
else
*o += 1;
}
}
return 0;
}
int main()
{
char a[100][100];
char *p[5];
int n;
scanf("%d", &n);
for (int i = 0 ; i < n; i++)
{
scanf(" %[^\n]s", &a[i][0]);
p[i] = &a[i][0];
}
int l, d, s, o;
f(p, n, &l, &d, &s, &o);
printf("%d %d %d %d", l, d, s, o);
return 0;
}