计算1到100之间不能被3整除的数字之和

Question

应用哪个循环结束语句呢 111111111111111111111111

Answer 1

#include <iostream>
using namespace std;
int main()
{
    int sum = 0;
    for (int i = 1; i <= 100; i++)
    {
        if (i % 3 != 0) sum += i;
    }
    cout << sum;
    return 0;
}