@RequestMapping(value={"/login"}, method=RequestMethod.GET)
public boolean login(HttpServletRequest request,
@Param(value = "number")String number,
@Param(value = "password")String password) throws UnsupportedEncodingException, NoSuchAlgorithmException {
number = request.getParameter("number");
password = request.getParameter("password");
// 获取加密后的密码 password
password = MD5Util.getEncryptedPwd(password);
// 获取数据库对应账户密码, findPasswordByAccount 查询数S据库账号的密码
// userService 业务实现内部调用userDao 去执行select 语句，可以吧
String encryptPassword = userMapper.findPasswordByNumber(number);
System.out.println(encryptPassword);
// 比对数据库中的密码 encryptPassword
if (password.equals(encryptPassword)) {
return true;
} else {
return false;
}
}
下面是有关方法的片段
//userMapper的
User login(String number,String password);
String findPasswordByNumber(String number);
//userService
void login(String number,String password);
String findPasswordByNumber(String number);
//userServiceImpl
@Override
public void login(String number,String password){
userMapper.login(number,password);
}
@Override
public String findPasswordByNumber(String number){
String password = userMapper.findPasswordByNumber(number);
return password;
}
//userMapper.xml
<select id="login" resultMap="result">
SELECT * FROM user where number=#{number} and password=#{password}
</select>
<select id="findPasswordByNumber" resultMap="result">
SELECT password FROM user where number=#{number}
</select>
如题出现的异常报错要怎么解决？想了半天也没弄懂，求大佬解答一下！！！
