dswqw66280 2017-02-13 05:50
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Jquery Ajax调用返回Parsererror?

I have written Jquery Ajax call but i got Parsererror.. in following js code i have checked which select element is changed in dynamic_slct. and i have checked generic or Company and then call GnrtTemp() with pass selected Element value.. if I select generic my follwing Code(function GnrtTemp and ajax call) is working.. if i select company i got Error parsererror.. my doubt is same ajax call working Generic and is not working as company.. what is the problem? How to fix that problem i have attached my js code and also PHP code .. If i did any mistake pls correct me.. suggest to solution.?

JS

$('#dynmic_slct').on("change", "#master ,select[name='company'], select[name='generic']", function(element){
    if(element.target.name == 'generic' || element.target.name == 'company')          {

            GnrtTemp(element.target.value);
}
});
function GnrtTemp(id){
    $.ajax({
        method: "POST",
        url: "ajaxRequest.php",
        dataType: "JSON",
        data: {fn: "getTemp", id: id},
        success: function(reqResult){},
        complete: function (jqXHR, textStatus) {
          alert(textStatus);
        }
    });
}

ajaxRequest.php

<?php

  $finalRes = array();
  if($_POST['fn'] == 'getTemp'){

        $template_src = getTemp($_POST['id']);

        $finalRes['result'] = $template_src;
        echo json_encode($finalRes);    
    }

    function getTemp($id){

       $db = new DB();

       $Query = "SELECT template_src
        FROM master
        WHERE refid =$id";

       $qryRes = $db->query($Query);

      return $qryRes;

   }

?>

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