获取数据问题，不能获取数据

Question

请问搜索后运行结果是1怎么回事啊？

import requests
import parsel

def get_response(html):
    headers = {

        "user-agent": "Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/103.0.0.0 Safari/537.36"
    }
    response = requests.get(html, headers=headers)

    return response

# 提取小说名称和所有章节的链接列表
def get_novel_info(html):
    html_data = get_response(html).text
    selector = parsel.Selector(html_data)
    name = selector.css(".info h1::text").get()

    href = selector.css(".listmain dd a::attr(href)").getall()

    link_list = ['https://www.bqgbe.com/' + i for i in href]

    return name, link_list


def get_content(html):
    link_data = get_response(html=html).text

    link_selector = parsel.Selector(link_data)

    print(link_selector)
    title = link_selector.css('.content h1::text').get()
    content = '\n'.join(link_selector.css('#chaptercontent::text').getall())
    return title, content


def save(name, title, content):
    with open(name + '.txt', mode='a', encoding='utf-8') as f:
        f.write(str(title))
        f.write('\n')
        f.write(str(content))
        f.write('\n')
    print('保存: ', title)

def search(word):

    search_url=f'https://www.bqgka.com/user/search.html?q={word}'

    json_data=get_response(html=search_url).json()
    print(json_data)

if __name__ == "__main__":
    search('弃宇宙')

    # url="https://www.bqgka.com/book/3315/"
    # name, link_list = get_novel_info(html=url)
    #
    # for link in link_list:
    #     title, content = get_content(html=link)
    #
    #     save(name=name, title=title, content=content)
    #     print(link)

Answer 1

看图片，你的47行代码的url过时了。
兄弟你需要重新定位一下