如何用Python搜取两个列表中的数并对应到文件中

Question

def save(content):
    filename='result.txt'
    with open(filename,mode='w')as fp:
        fp.write(str(content))
s=[35,31,41,28,45,45,50,30,56,49,38,38,51,57,26,32,45,33,56,28,
   42,36,35,44,37,47,28,59,46,50,47,32,52,39,47,35,55,29,37,43,
   39,34,55,35,41,55,36,59,46,57,41,47,52,27,42,36,32,43,32,
   40,49,39,53,37,34,36,56,43,48,51,32,35,38,43,47,48,34,57,31,55,
   31,40,47,41,36,34,30,44,55,50,59,28,33,47,48,43,33,53,38,27,50,
   55,43,32,44,53,31,55,33,40,49,58,40,53,49,46,27,52,25,43,47,49,
   49,35,49,25,47,43,59,25,58,57,54,31,43,33,47,30,34,35,27,40,
   25,25,27,27,50,45,47,34,51,44,27,33,57,53,50,52,50,36,54,49,
   38,45,31,40,59,32,34,50,46,52,28,34,59,52,59,32,34,48]
t=[1,1,1,0,1,1,0,0,1,0,1,0,1,0,1,1,1,1,0,1,0,0,1,0,0,1,0,0,0,0,
   1,0,0,0,0,0,0,0,0,0,0,0,1,1,1,1,1,1,0,0,1,1,0,1,0,0,1,0,0,0,
   0,0,0,1,1,1,0,1,0,1,0,1,1,0,1,1,1,0,1,1,1,0,1,0,1,0,0,1,1,0,
   1,0,1,0,0,1,1,0,0,0,1,0,0,1,1,1,1,1,1,0,0,0,1,1,1,1,0,0,1,0,
   0,0,0,1,1,1,0,0,1,1,1,0,0,0,0,0,0,1,0,0,0,0,0,1,1,1,1,0,1,1,0,
   0,1,0,1,0,1,0,0,0,0,1,0,0,0,0,1,0,1,0,1,0,1,0,1,0,0,1,1,0]

列表s表示教职工的年龄，列表t是对应的调查结果，1表示已接种疫苗，0表示未接种
编写程序统计30~50岁（包括30,50）已接种疫苗的教职工数，并存入‘result.txt’中
如何用Python解决此类问题

Answer 1

• 用zip函数遍历统计数据，记录符合条件的信息就好。
   
  代码运行效果截屏图片
  

  

python代码

#!/sur/bin/nve python
# coding: utf-8


def save(content):
    filename='result.txt'
    with open(filename,mode='w')as fp:
        fp.write(str(content))

s=[35,31,41,28,45,45,50,30,56,49,38,38,51,57,26,32,45,33,56,28,42,36,35,44,37,47,28,59,46,50,47,32,52,39,47,35,55,29,37,43,39,34,55,35,41,55,36,59,46,57,41,47,52,27,42,36,32,43,32,40,49,39,53,37,34,36,56,43,48,51,32,35,38,43,47,48,34,57,31,55,31,40,47,41,36,34,30,44,55,50,59,28,33,47,48,43,33,53,38,27,50,55,43,32,44,53,31,55,33,40,49,58,40,53,49,46,27,52,25,43,47,49,49,35,49,25,47,43,59,25,58,57,54,31,43,33,47,30,34,35,27,40,25,25,27,27,50,45,47,34,51,44,27,33,57,53,50,52,50,36,54,49,38,45,31,40,59,32,34,50,46,52,28,34,59,52,59,32,34,48]
t=[1,1,1,0,1,1,0,0,1,0,1,0,1,0,1,1,1,1,0,1,0,0,1,0,0,1,0,0,0,0,1,0,0,0,0,0,0,0,0,0,0,0,1,1,1,1,1,1,0,0,1,1,0,1,0,0,1,0,0,0,0,0,0,1,1,1,0,1,0,1,0,1,1,0,1,1,1,0,1,1,1,0,1,0,1,0,0,1,1,0,1,0,1,0,0,1,1,0,0,0,1,0,0,1,1,1,1,1,1,0,0,0,1,1,1,1,0,0,1,0,0,0,0,1,1,1,0,0,1,1,1,0,0,0,0,0,0,1,0,0,0,0,0,1,1,1,1,0,1,1,0,0,1,0,1,0,1,0,0,0,0,1,0,0,0,0,1,0,1,0,1,0,1,0,1,0,0,1,1,0]

result = [] # 30~50已接种疫苗统计列表初值。

for i in zip(s, t): # 遍历统计数据。
    
    if 30 <= i[0] <= 50 and i[1]:
        result += [i] # 这里也可以是[1]。
    else:
        result += [0]

print(f"\n统计结果数据：\n{result}\n共计{len([i for i in result if i])}人。") # 调试用语句。
save(result) # 统计结果写入文件。

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