使用js对数据循环遍历处理

Question

arr1.length = 6
arr1[0].length = 10
arr1[1].length = 8
arr1[2].length = 17
arr1[3].length = 5
arr1[4].length = 12
arr1[5].length = 8
arr2 = [1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20,21,22,23,24,25,26,27,28,29,30,31,32,33,34,35,36,37,38,39,40,41,42,43,44,45,46,47,48,49,50,51,52,53,54,55,56,57,58,59,60]

需要将arr2的元素替换到arr1中，并且按照arr1的二维结构，将arr2中的元素逐个填入，用js完成

Answer 1

let arr1 = [
  new Array(10),
  new Array(8),
  new Array(17),
  new Array(5),
  new Array(12),
  new Array(8)
];

let arr2 = [1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20,21,22,23,24,25,26,27,28,29,30,31,32,33,34,35,36,37,38,39,40,41,42,43,44,45,46,47,48,49,50,51,52,53,54,55,56,57,58,59,60];

let k = 0; // 用于遍历 arr2 的索引

for (let i = 0; i < arr1.length; i++) {
  for (let j = 0; j < arr1[i].length; j++) {
    arr1[i][j] = arr2[k];
    k++;

    // 如果遍历完 arr2，则跳出循环
    if (k === arr2.length) {
      break;
    }
  }
}