拿到一个yuv格式的数据
public Bitmap rawByteArray2RGBABitmap2(byte[] data, int width, int height) {
int frameSize = width * height;
int[] rgba = new int[frameSize];
for (int i = 0; i < height; i++)
for (int j = 0; j < width; j++) {
int y = (0xff & ((int) data[i * width + j]));
int u = (0xff & ((int) data[frameSize + (i >> 1) * width + (j & ~1) + 0]));
int v = (0xff & ((int) data[frameSize + (i >> 1) * width + (j & ~1) + 1]));
y = y < 16 ? 16 : y;
y = y > 235 ? 235: y;
int r = Math.round(1.164f * (y - 16) + 1.596f * (v - 128));
int g = Math.round(1.164f * (y - 16) - 0.813f * (v - 128) - 0.391f * (u - 128));
int b = Math.round(1.164f * (y - 16) + 2.018f * (u - 128));
r = r < 0 ? 0 : (r > 255 ? 255 : r);
g = g < 0 ? 0 : (g > 255 ? 255 : g);
b = b < 0 ? 0 : (b > 255 ? 255 : b);
rgba[i * width + j] = 0xff000000 + (b << 16) + (g << 8) + r;
}
Bitmap bmp = Bitmap.createBitmap(width, height, Bitmap.Config.ARGB_8888);
bmp.setPixels(rgba, 0 , width, 0, 0, width, height);
return bmp;
}
用这个去转换成bitmap,结果是
基本还是黑白,然后上面会有一些色斑