如何回显上次上传文件的名称

Question

I was asked that the output file should only output the name and id of the last person who uploaded a file with a specific name. confusing right? even I am confused. so let me give an example

let us say that you have 3 employees registered in your company. lets call them

1. Pikachu,
2. Raichu and
3. Pichu.

Pikachu has 3 files uploaded in the company, Raichu has 2 files uploaded and Pichu has also 2 files uploaded. The files must also be ordered according to employeename(ASC) and filename(DESC). Mine is already in ordered by. This is my only problem. In this case the output should look like this:

*noticed that the employee name and employee id is in the last file uploaded?? does anyone knows how to do that?please i beg you guys to help me out here T-T the task is way too hard and im just a rookie

Im thinking of using 2 tables here. table 1 for the employee id and employee name, table 2 for the file name, etc. so i guess this would also involve 2 while clause. i have the idea but i dont know how to mix them all up.

my code before I edited it like sir vincent look like this:

if ($_SESSION[$fgmembersite->GetLoginSessionVar()] == 'sa' 
   OR $_SESSION[$fgmembersite->GetLoginSessionVar()] == 'admin')
{                                   

  $sql= "select * from gmdc_employee 
         where employee_name like '%$search%' 
         AND employee_name like '$listname%'";
} else {
  $sql = "select b.* from gmdc_user a, gmdc_employee b 
          where a.username = '".$_SESSION[$fgmembersite->GetLoginSessionVar()]."' 
          AND a.company_id = b.company_id 
          AND b.employee_name like '$listname%' 
          AND b.employee_name like '%$search%'"; 
}
$query = mysql_query("$sql ORDER BY employee_name,confirmation DESC 
                     ,file_id DESC,file_date DESC 
                      LIMIT $offset,$limit") or die ( mysql_error () );
$result = mysql_query($sql) or die (mysql_error());
$total = mysql_num_rows($result);

if(!$result || mysql_num_rows($result) <= 0)
{
  $fgmembersite->HandleError("No file found.");
  return false;
}
while ($row = mysql_fetch_assoc($query))
{
  $file_id = $row['file_id'];
  $file_desc = $row['file_description'];
  $file_date = $row['file_date'];
  $file_name = $row['file_name'];
  $file_accs = $row['folder_access'];
  $file_employee  = $row['employee_id'];
  $file_confir = $row['confirmation'];
  $file_ename = ucwords($row['employee_name']);

  $info = pathinfo($file_name);
  $file_ext = $info['extension'];

  echo '<tr><td>&nbsp;</td></tr>
        <tr class="subone"><td class="sub" width="100">'.$file_employee.'<br />
        &nbsp;</td>';
  if($_SESSION[$fgmembersite->GetLoginSessionVar()] == 'sa')
  {
    ?>
    <td class="sub" width="100">
    <a href="" onclick = javascript:newPopup('addfile.php?emp=
    <?php echo $file_employee ?>');><?php echo$file_ename?></a>
    <br />&nbsp;</td>
    <?php
  } else {
    echo '<td class="sub" width="182">'.$file_ename.'<br />&nbsp;</td>';
  }
  echo'<td  class="sub" width="218">
       <a href="'.$file_accs.$file_name.'" target="_blank" 
        style="text-decoration: underline;">'.$file_desc.'</a>
       <br />&nbsp;</td><td  class="sub" width="100">
      '.date('M d, Y',mktime(0,0,0,substr($file_date,5,2)
       ,substr($file_date,8,2),substr($file_date,0,4))).'
       <br />&nbsp;</td><td  class="sub" width="100">'.$file_confir.'
       <br />&nbsp;</td>';

  if($_SESSION[$fgmembersite->GetLoginSessionVar()] == 'sa')
  {
    if($file_confir == 'Pending' OR $file_confir == 'NotApproved')
    {
      if(isset($_GET['id']))
      {
        $fgmembersite->Delete_Db($_GET['id']);
      }
      echo '<td  class="sub" width="100">
            <a href="index.php?id='.$file_id.'">Delete</a>
            <br />&nbsp;</td>';
    }
  }
  else if($_SESSION[$fgmembersite->GetLoginSessionVar()] == 'admin')
  {
    if($file_confir == 'Pending')
      {
        if(isset($_GET['yes']))
        {
          $fgmembersite->UpdateYesDB($_GET['yes']);
          //echo "<script>location.reload();</script>";
        }
        else if(isset($_GET['no']))
        {
          $fgmembersite->UpdateNoDB($_GET['no']);
          //echo "<script>location.reload();</script>";
        }
        if (!isset($_GET['offset'])) {
          $prevoffset = 0;
        } else {
          $prevoffset = $_GET['offset'];
          echo'<td  class="sub" width="100">
          <a href="index.php?offset='.$prevoffset.'&searchfile='.$search.'
           &namelist='.$listname.'&yes='.$file_id.'">Approve</a>
           //there's a link here<br /><br />
           <a href="index.php?offset='.$prevoffset.'&searchfile='.$search.'
            &namelist='.$listname.'&no='.$file_id.'">NotApprove</a>
            //there's a link here
            &nbsp;</td> ';
      }
    }
  }?>

Just ignore every if($_SESSION[$fgmembersite->GetLoginSessionVar()] == 'admin') and whatever, this is for different output since my file can be logged into by 3 different users. SA(programmers), admin(the approver of the file uploaded), and user(company). There are TD and TR there as well, I don't know why wont it appear here.

output looked like this:

employee_id  +   employee_name  +  file_name
3            |   pichu          |  file6
3            |   pichu          |  file1
1            |   pikachu        |  file7
1            |   pikachu        |  file4
1            |   pikachi        |  file3
2            |   raichu         |  file8
2            |   raichu         |  file5
2            |   raichu         |  file2

and I want my output to be like this:

***OUTPUT***

**employee_id        employee_name              file_name**
    3                      pichu                        file6
                                                        file1
    1                     pikachu                       file7
                                                        file4
                                                        file3
    2                     raichu                        file5
                                                        file2

for example that raichu uploaded another file, the output should now look like this:

OUTPUT

**employee_id        employee_name            file_name**
    3                      pichu                      file6
                                                      file1
    1                      pikachu                    file7
                                                      file4
                                                      file3
    2                      raichu                     file8
                                                      file5
                                                      file2

Answer 1

Using Vincent table structure will likely solve your problem. And to get the result you wanted, you can use single query using join for the two table. So there's no need to use two query.

SELECT  e.employee_id as employee_id,            //Display column for employee_id
        e.employee_name as employee_name,        
        f.file_name as file_name
  FROM employee e                                // The e is an alias for table
 INNER JOIN file f                               // The inner join will return all the rows which have same employee_id on both table 
    ON e.employee_id = f.employee_id
 ORDER BY e.employee_name, f.file_name DESC;     // Order of the result default is ASC

UPDATE

I assume you have two tables and the structure is same with Vincent. Now This query will get the data on two tables. The join part here is that, when an employee_id on employee table has a same employee_id on the file table, this will return a row. Please see mysql join for more information. Then the order e.employee_id is the employee_id on employee table, since there's no order specified it will use the default which is ascending.

Then output of the above query could be the below code.

employee_id  +   employee_name  +  file_name
3            |   pichu          |  file6
3            |   pichu          |  file1
1            |   pikachu        |  file7
1            |   pikachu        |  file4
1            |   pikachi        |  file3
2            |   raichu         |  file8
2            |   raichu         |  file5
2            |   raichu         |  file2

You will notice that employee_id and employee_name is repeated. This is because the query include all the columns value in a row that specified in SELECT column_name. You can filter the duplicate value in your php, specially if you will store it first in an object rather than directly printing it.

PHP

$query = $see_the_query_above;
$result = mysql_query($query) or die(mysql_error($db));
$emp_id = "";     //This will be use to remove employee_id if its already echoed.
$emp_name = "";   //This will be use to remove employee_name if its already echoed.

echo '<table>';
echo '<tr><th>employee_id</th><th>employee_name</th><th>file_name</th></tr>';

while ($row = mysql_fetch_assoc($result)) {
    //Check $emp_id and $emp_name if same with the current, if same just print nothing or space else replace it with new.
    $emp_id = $emp_id == $row['employee_id'] ? "" : $row['employee_id']
    $emp_name = $emp_name == $row['employee_name'] ? "" : $row['employee_name'];

    echo '<tr>';
    echo '<td>'.$emp_id.'<td>';
    echo '<td>'.$emp_name.'</td>';
    echo '<td>'.$row['file_name'].'</td>';
    echo '</tr>';
}
echo '</table>';