电影计量,检测内容需要包括:
总时长(秒)
镜头数
最短镜头(秒)
最长镜头(秒)
平均镜头时长ASL(秒)
镜头长度中值MSL
电影计量代码检测内容包括总时长(秒) 镜头数 最短镜头(秒) 最长镜头(秒) 平均镜头时长ASL(秒) 镜头长度中值MSL
- 写回答
- 好问题 0 提建议
- 关注问题
- 邀请回答
-
3条回答 默认 最新
关注让阿豪来帮你解答,本回答参考chatgpt3.5编写提供,如果还有疑问可以评论或留言
问题:如何对电影进行计量,并得出总时长、镜头数、最短镜头、最长镜头、平均镜头时长和镜头长度中值? 回答: 一、 总时长 可以使用Python中的moviepy模块来读取视频文件,并得到总时长。 代码示例:from moviepy.video.io.VideoFileClip import VideoFileClip video_path = "movie.mp4" video = VideoFileClip(video_path) duration = video.duration print("总时长为:", duration)二、 镜头数 同样可以使用moviepy模块,读入视频后通过获取视频中的所有帧并遍历它们获取镜头数。 代码示例:
from moviepy.video.io.VideoFileClip import VideoFileClip video_path = "movie.mp4" video = VideoFileClip(video_path) frames = video.reader.nframes print("镜头数为:", frames)三、 最短镜头 利用moviepy模块中的
iter_frames()方法遍历所有的帧,并记录下最小帧数所对应的时间,即为最短镜头。 代码示例:from moviepy.video.io.VideoFileClip import VideoFileClip video_path = "movie.mp4" video = VideoFileClip(video_path) min_duration = float('inf') for frame in video.iter_frames(): duration = video.duration / len(video.reader) if duration < min_duration: min_duration = duration print("最短镜头为:", min_duration)四、 最长镜头 同理,利用
iter_frames()方法遍历所有的帧,并记录下最大帧数所对应的时间,即为最长镜头。 代码示例:from moviepy.video.io.VideoFileClip import VideoFileClip video_path = "movie.mp4" video = VideoFileClip(video_path) max_duration = 0 for frame in video.iter_frames(): duration = video.duration / len(video.reader) if duration > max_duration: max_duration = duration print("最长镜头为:", max_duration)五、 平均镜头时长ASL 通过前面的代码,我们已经可以得到总时长和镜头数,在此基础上可以得出平均镜头时长。 代码示例:
from moviepy.video.io.VideoFileClip import VideoFileClip video_path = "movie.mp4" video = VideoFileClip(video_path) duration = video.duration frames = video.reader.nframes asl = duration / frames print("平均镜头时长为:", asl)六、 镜头长度中值MSL 首先按照时间戳将所有镜头长度存入一个列表中,然后对该列表进行排序,取中间的元素作为镜头长度中值即可。 代码示例:
from moviepy.video.io.VideoFileClip import VideoFileClip video_path = "movie.mp4" video = VideoFileClip(video_path) durations = [] for frame in video.iter_frames(): duration = video.duration / len(video.reader) durations.append(duration) durations.sort() n = len(durations) if n % 2 == 0: msl = (durations[n//2-1] + durations[n//2]) / 2 else: msl = durations[n//2] print("镜头长度中值为:", msl)整合代码示例:
from moviepy.video.io.VideoFileClip import VideoFileClip video_path = "movie.mp4" video = VideoFileClip(video_path) # 计算总时长 duration = video.duration # 计算镜头数 frames = video.reader.nframes # 计算最短镜头 min_duration = float('inf') for frame in video.iter_frames(): duration = video.duration / len(video.reader) if duration < min_duration: min_duration = duration # 计算最长镜头 max_duration = 0 for frame in video.iter_frames(): duration = video.duration / len(video.reader) if duration > max_duration: max_duration = duration # 计算平均镜头时长ASL asl = duration / frames # 计算镜头长度中值MSL durations = [] for frame in video.iter_frames(): duration = video.duration / len(video.reader) durations.append(duration) durations.sort() n = len(durations) if n % 2 == 0: msl = (durations[n//2-1] + durations[n//2]) / 2 else: msl = durations[n//2] print("总时长为:", duration) print("镜头数为:", frames) print("最短镜头为:", min_duration) print("最长镜头为:", max_duration) print("平均镜头时长为:", asl) print("镜头长度中值为:", msl)本回答被题主选为最佳回答 , 对您是否有帮助呢?解决 无用评论 打赏 举报