我的模态对话框表单没有使用ajax提交给php中的控制器

Question

In modal dialog form submit value are not passed in to the my controller

function save()
{
    var url;
    url = "<?php echo site_url('index.php/User/book_update')?>";
    $.ajax({
        url : url,
        type: "POST",
        data: $('#form').serialize(),
        dataType: "JSON",
        success: function(data)
        {
            $('#modal_form').modal('hide');
        },
        error: function (jqXHR, textStatus, errorThrown)
        {
            alert('Error adding / update data');
        }
    });
}

while submitting form button no response only Error adding / update data shows

            public function book_update()
            {
            $markid= $this->input->post('markid');
            $subcode=$this->input->post('subcode');
            echo $markid;
            echo $subcode;
            }

Answer 1

Hope this will help you

Your url should be like this :

url = "<?php echo site_url('User/book_update')?>";

Instead of this :

url = "<?php echo site_url('index.php/User/book_update')?>";

js function should be like this :

function save()
{
    var url;
    url = "<?php echo site_url('User/book_update')?>";
    $.ajax({
        url : url,
        type: "POST",
        data: $('#form').serialize(),
        dataType: "JSON",
        success: function(data)
        {
            $('#modal_form').modal('hide');
        },
        error: function (jqXHR, textStatus, errorThrown)
        {
            alert('Error adding / update data');
        }
    });
}

Your controller's book_update method should be like this :

public function book_update()
{
   $markid = $this->input->post('markid');
   $subcode = $this->input->post('subcode');
   $array = array('markid' => $markid);
   echo json_encode($array);
   exit;
}