dongzhong9055 2018-02-28 06:05
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将mysql数据作为json feed发送给另一个开发人员

I have the following code;

// check phone exist or not
   $query = "SELECT * FROM user WHERE phone_number=".$phone;
   $result = mysqli_query($conn,$query);
   $count = mysqli_num_rows($result);
   if($count!=0){
    $error = true;
    $phoneError = "Provided Phone Number($phone) is already in use.";
   }

How can i send the result of the query as json feed to my colleague who we are working on the same project?

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  • duanmuybrtg1231 2018-02-28 06:19
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    You need to create an array, where you can add status like fail/success and corresponding messages based on that.

    A sample code is given below:-

    $final_message = []; 
    if($count > 0){ 
      $final_message['status'] = 'fail'; 
      $final_message['message'] = "Provided Phone Number($phone) is already in use."; 
    }else{ 
      $final_message['status'] = 'success'; 
    } 
    echo json_encode($final_message);
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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