dongqiu3709 2018-01-29 09:03
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为每个隐藏值实现唯一的id名称

I am trying to implement an unique id name for each hidden inputs inside while conditions suppose I have this code

while(mysqli_stmt_fetch($stmt)):

<button class="btn btn-success btn-xs" onclick="InitTime(<?php echo $row_id; ?>)">Send</button>

<input type="hidden" id="on" value="<?php echo $row_id; ?>">

endwhile; 

function InitTime(row_id, on) {
    var conf = confirm("Are you sure to execute <?php echo $row_id; ?>");
    var on = $("#on").val();
    if (conf == true) {
        $.post("ajax/initializeTime.php", {
                row_id: row_id,
                on:on
             }
        );
    }
}

But each time I click the button I get the first row ID from DB but it suppose to be different ID which is comes from DB

And in my initializeTime.php I retrieve same ID

if(isset($_POST['row_id']) AND isset($_POST['on']) )
{
     //Here I retrieve the first ID from DB 
}
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1条回答 默认 最新

  • dpxnrx11199 2018-01-29 09:09
    关注

    The problem is you have multiple id on. ID should be unique.

    You can so something like:

    while(mysqli_stmt_fetch($stmt)):
    
    <button class="btn btn-success btn-xs" onclick="InitTime(<?php echo $row_id; ?>)">Send</button>
    
    <input type="hidden" id="on<?php echo $row_id; ?>" value="<?php echo $row_id; ?>">
    
    endwhile; 
    

    The id should now be on1, on2 and so on..

    On your js:

    function InitTime(row_id) {
        var conf = confirm("Are you sure to execute " + row_id +"?");
        var on = $("#on" + row_id).val();
        if (conf == true) {
            $.post("ajax/initializeTime.php", {
                    row_id: row_id,
                    on:on
                 }
            );
        }
    }
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
    评论

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