dsunj08246 2017-12-27 20:03
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如何在PHP中使用PDO获取MS SQL存储过程返回值?

Simple example

CREATE PROCEDURE [dbo].[InsertLoginInPHP]
    @login as nvarchar(50), @password as nvarchar(50), @resultOK as int, @resultnot as int

AS
BEGIN
    SET @resultOK = 10
    SET @resultnot = 1

    IF EXISTS (SELECT * FROM Users WHERE Login = @login)
        BEGIN
            SELECT @resultnot as return // 1
        END
    ELSE
        BEGIN
            INSERT INTO Users (Login,Password) VALUES(@login,@password)
            SELECT @resultOK as return // 10
        END
END

and In php

$query = ("EXECUTE InsertLogin :login, :password");
$query_stored = $conn->prepare($query);
$query_stored->bindvalue(':login', $login);
$query_stored->bindvalue(':password', $password);   
$query_stored->execute();

How can I get return value ( @resultnot or @resultOK ) in php? And How can I get and use return value in JSON? Like this

json_encode(array('status'=>'Ok','return'=>$query_sotored[resultOK])));
  • 写回答

1条回答 默认 最新

  • douzou8074 2017-12-27 20:52
    关注

    You need to fetch a row from the statement, then access the column from the array this returns.

    $query = ("EXECUTE InsertLogin :login, :password");
    $query_stored = $conn->prepare($query);
    $query_stored->bindvalue(':login', $login);
    $query_stored->bindvalue(':password', $password);   
    $query_stored->execute();
    $row = $query_stored->fetch(PDO::FETCH_ASSOC);
    echo json_encode(array('status'=>'Ok','return'=>$row['return'])))
    
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