删除部分URI，然后传递给脚本

Question

Currently my .htaccess looks like this:

RewriteEngine On
RewriteCond %{REQUEST_FILENAME} !-f
RewriteCond %{REQUEST_FILENAME} !-d
RewriteRule . /index.php [QSA]

All URIs are passed to the PHP script which then parses it and returns stuff.

Now I want to implement a versioning system, in which there would be different script handling the URIs depending on the version called.

That is:

• if I call /v1/countries/es/users, I want to pass the URI /countries/es/users to the script v1.php
• if I call /v2/users/314/settings, then I want the URI /users/314/settings passed to the script v2.php

I tried doing something like

RewriteRule ^/?v(\d)/.*$ v$1.php [QSA]

That would send execution to the version-specific script, but I still want to strip out the /v1/ initial part of the URI when passed to the script, i.e., I want the script to receive the URI without the initial version part. How can I achieve that?

Answer 1

It clearly explains in apache document: Apache mod_rewrite Introduction.

You could pass it as parameter, and use $_GET['route'] to get the URI part without first version part:

RewriteRule ^/v(\d)/(.*)$ v$1.php?param1=$2 [QSA,L]
RewriteRule ^/v(\d)/(.*)/(.*)$ v$1.php?param1=$2&param2=$3 [QSA,L]