abaqus脚本定义梁截面方向

Question

abaqus脚本定义梁截面方向

通过abaqus脚本定义梁截面方向问题，选择了圆形梁截面，但是每个梁轴向方向都一样，无法一起框选，如何解决问题

Answer 1

本答案参考ChatGPT-3.5

问题分析：该问题意思是通过abaqus脚本定义梁截面方向时，选择的是圆形梁截面，但是每个梁轴向方向都一样，导致无法一起框选。该问题需要解决才能正确地定义梁截面方向。

解决方案：

1.定义圆柱体的顶点和轴向单位向量：

import math

# 定义圆柱体高度、半径、截面单位向量
h, r = 100.0, 10.0
n = 10
theta = 2 * math.pi / n
axis = (0, 0, 1)

# 计算圆柱体顶点
for i in range(n):
    x = r * math.cos(i * theta)
    y = r * math.sin(i * theta)
    z = 0
    print("v {} {} {}".format(x, y, z))
    
# 计算圆柱体截面的单位向量
for i in range(n):
    x = r * math.cos(i * theta)
    y = r * math.sin(i * theta)
    z = 0
    v1 = (0, 0, 1)
    v2 = (x, y, z)
    cross = (v1[1] * v2[2] - v2[1] * v1[2], v2[0] * v1[2] - v1[0] * v2[2], v1[0] * v2[1] - v2[0] * v1[1])
    length = math.sqrt(cross[0] ** 2 + cross[1] ** 2 + cross[2] ** 2)
    unit_vector = (cross[0] / length, cross[1] / length, cross[2] / length)
    print("axial_direction {} {} {}".format(unit_vector[0], unit_vector[1], unit_vector[2]))

2.定义梁截面法向量：

import math

# 定义圆柱体高度、半径、截面单位向量
h, r = 100.0, 10.0
n = 10
theta = 2 * math.pi / n
axis = (0, 0, 1)

# 计算圆柱体截面法向量
for i in range(n):
    x = r * math.cos(i * theta)
    y = r * math.sin(i * theta)
    z = 0
    v1 = (0, 0, 1)
    v2 = (x, y, z)
    cross = (v1[1] * v2[2] - v2[1] * v1[2], v2[0] * v1[2] - v1[0] * v2[2], v1[0] * v2[1] - v2[0] * v1[1])
    length = math.sqrt(cross[0] ** 2 + cross[1] ** 2 + cross[2] ** 2)
    unit_normal = (cross[0] / length, cross[1] / length, cross[2] / length)
    print("cross_direction {} {} {}".format(unit_normal[0], unit_normal[1], unit_normal[2]))

3.定义梁的轨迹和方向，以及梁的截面法向量和轴向方向

import math

# 定义圆柱体高度、半径、截面单位向量
h, r = 100.0, 10.0
n = 10
theta = 2 * math.pi / n
axis = (0, 0, 1)

# 计算圆柱体顶点
for i in range(n):
    x = r * math.cos(i * theta)
    y = r * math.sin(i * theta)
    z = 0
    print("v {} {} {}".format(x, y, z))
    
# 计算圆柱体截面的单位向量和法向量
for i in range(n):
    x = r * math.cos(i * theta)
    y = r * math.sin(i * theta)
    z = 0
    v1 = (0, 0, 1)
    v2 = (x, y, z)
    cross = (v1[1] * v2[2] - v2[1] * v1[2], v2[0] * v1[2] - v1[0] * v2[2], v1[0] * v2[1] - v2[0] * v1[1])
    length = math.sqrt(cross[0] ** 2 + cross[1] ** 2 + cross[2] ** 2)
    unit_vector = (cross[0] / length, cross[1] / length, cross[2] / length)
    print("axial_direction {} {} {}".format(unit_vector[0], unit_vector[1], unit_vector[2]))
    print("cross_direction {} {} {}".format(cross[0], cross[1], cross[2]))
    
# 计算梁的轨迹和方向，以及梁的截面法向量和轴向方向
for i in range(n):
    x1, y1, z1 = r * math.cos(i * theta), r * math.sin(i * theta), 0.0
    x2, y2, z2 = r * math.cos((i + 1) * theta), r * math.sin((i + 1) * theta), 0.0
    x3, y3, z3 = r * math.cos(i * theta), r * math.sin(i * theta), h
    x4, y4, z4 = r * math.cos((i + 1) * theta), r * math.sin((i + 1) * theta), h

    print("beam_part, {0:g}, {1:g}, {2:g}, {3:g}, {4:g}, {5:g}, {6:g}, {7:g}, {8:g}, {9:g}, {10:g}, {11:g}".format(x1, y1, z1, \
          x2, y2, z2, x3, y3, z3, x4, y4, z4))
    # 梁截面正常方向
    print("part_surface, beam_part, circle_beam_cross_section_{0:g}, y, lateral, -.1e-4, {1:g}, {2:g}, {3:g}".format(i, unit_normal[0], \
      unit_normal[1], unit_normal[2]))
    # 梁轴向方向
    print("part_orientation, beam_part, circle_beam_axial_section_{0:g}, {1:g}, {2:g}, {3:g}".format(i, unit_vector[0], \
      unit_vector[1], unit_vector[2]))

以上是针对abaqus脚本定义梁截面方向问题的具体解决方案，可以通过以上三部分代码来解决该问题。