dongma2388 2012-01-09 01:16
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如何使用jquery获取json数据并在div中显示

Let's say .. I have the following script in my controller:

 $result= array("Name"=>Charlie Sheen, "Age"=>30); 
 echo josn_encode($result);

And in my view file I have the following java script. Now could you please tell me what exactly to write in the success function of the script below in order to get the "Name" and "Age" displayed in two different divs inside body tag? I have found some tutorials on this but all those are very confusing to me. Could you please kindly help?

Thanks in Advance :)

<script  type="text/javascript">
 $(function(){ // added

     $('a.read').click(function(){
            var a_href = $(this).attr('href'); 

     $.ajax({

     type: "POST",
     url: "<?php echo base_url(); ?>batch/get_info",
     data: "id="+a_href,
     success: function(server_response){
                                                  //What exactly to write here
                                         }                                      
                                            }); //$.ajax ends here                          
                                                return false    

    });//.click function ends here

  }); // function ends here                        

 </script>  
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2条回答 默认 最新

  • dongxian8858 2012-01-09 01:24
    关注

    Make sure you spell you json_encode function correctly.

    Your html should look like this:

    <head>
    
    <script  type="text/javascript">
    $(function(){ // added
    
     $('a.read').click(function(){
         var a_href = $(this).attr('href'); 
    
         $.ajax({
    
            dataType : 'json', //You need to declare data type
    
            type: "POST",
            url: "<?php echo base_url(); ?>batch/get_info",
            data: "id="+a_href,
            success: function(server_response){
               $( '#name' ).text( server_response.Name );
               $( '#age' ).text( server_response.Age);
            }                                      
          }); //$.ajax ends here                          
          return false    
    
       });//.click function ends here
    
    }); // function ends here                        
    
    </script>  
    
    </head>
    <body>
    
       <div id='name'></div>
       <div id='age'></div>
    
    </body>
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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  • dsp15140275697 2012-01-09 01:20
    关注

    First of all, you should set the dataType. It should have the value 'json'. As for accessing it, you just access it as you would any other JavaScript object:

    <script type="text/javascript">
    $(function() {
         $('a.read').click(function() {
             var a_href = $(this).attr('href'); 
    
             $.ajax({
                 type: "POST",
                 url: "<?php echo base_url(); ?>batch/get_info",
                 data: "id=" + a_href,
                 dataType: 'json',
                 success: function(result) {
                    alert(result.Name); // Charlie Sheen 
                 }                                      
             });
    
             return false;
        });
    });
    </script>
    
    评论
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