dsq30861 2011-05-01 13:01
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如何使用PHP将MySQL的记录转换为值对象

I have this code:

$Result = DBQuery("SELECT user_id,nick_name,email FROM users LIMIT $fromindex.",".$numOfUsers);
if ($Result)
{
     $resultUsers->UersData=$Result;
}

The problem is that the results U get are in some kind of format that i don't know.

I want to get the results in array format, which every element of that array should be a value object class of this type:

class UserVO {
    var $_explicitType="UserVO";

    var $id;

    var $nickName;

    var $email;
}

Any idea how it can be done?

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2条回答 默认 最新

  • doushui5587 2011-05-01 13:10
    关注

    My answer might not sound very helpful, regarding your unclear question. I am supposing, that the function DBquery returns the result of mysql_query(......). If thats true, then you are feeding the userData with a Resource string which is a resource data type.

    There are few ways to access such resource String

    1. If the query exports multiple results

      while($row = mysql_fetch_assoc($userData) {
         print_r($row); //This is where you will get your mysql rows.
      }
      
    2. If the query return single row

      $row = mysql_fetch_assoc($userData);
      print_r($row); // //This is where you will get your mysql rows.
      

    Here are some must check links

    评论

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