考虑标点符号从文本中提取单词

Question

considering i have an offset marking the start of the word.. i need a method to get the size of that word considering all the sign of punctuation.

example:

$str = "my text bla bla-bla; hello! abc";
$offset = "22";  // start of hello

now i need a function that returns 5 considering hello is 5 chars.

this are some of punctuations may occur:

array(',','.',' ','-',"'",'"',';',':','?','!','|','/','\\','<','>')

i can do some hard parsing but i would like to write something more elegant

Answer 1

This should help you:

function getWordSize($string, $offset = 0)
{
    $word = array();

    if (preg_match('~.{' . max(0, intval($offset)) . '}(\p{L}+)~u', $string, $word) > 0)
    {
        if (array_key_exists(1, $word) === true)
        {
            return strlen($word[1]); // bytes, or
            return strlen(utf8_decode($word[1])); // unicode chars
        }
    }

    return 0;
}

Usage:

echo getWordSize('my text bla bla-bla; hello! abc', 21); // 5

However this doesn't handle offsets that cut words in middle, so:

echo getWordSize('my text bla bla-bla; hello! abc', 23); // 3