I am using the below PHP file to upload XML to MySQL database, but the issue is my table name is Con-1 and cannot use it. I have error in the below line:
array(
':name' => $data->Con-1[$i]->name,
':address' => $data->Con-1[$i]->address,
':gender' => $data->Con-1[$i]->gender,
':designation' => $data->Con-1[$i]->designation,
':age' => $data->Con-1[$i]->age
)
please help me to solve it
<?php
//import.php
sleep(3);
$output = '';
if(isset($_FILES['file']['name']) && $_FILES['file']['name'] != '')
{
$valid_extension = array('xml');
$file_data = explode('.', $_FILES['file']['name']);
$file_extension = end($file_data);
if(in_array($file_extension, $valid_extension))
{
$data = simplexml_load_file($_FILES['file']['tmp_name']);
$connect = new PDO('mysql:host=localhost;dbname=testing','root', '');
$query = "
INSERT INTO `Con-1`
(name, address, gender, designation, age)
VALUES(:name, :address, :gender, :designation, :age);
";
$statement = $connect->prepare($query);
for($i = 0; $i < count($data); $i++)
{
$statement->execute(
array(
':name' => $data->Con-1[$i]->name,
':address' => $data->Con-1[$i]->address,
':gender' => $data->Con-1[$i]->gender,
':designation' => $data->Con-1[$i]->designation,
':age' => $data->Con-1[$i]->age
)
);
}
$result = $statement->fetchAll();
if(isset($result))
{
$output = '<div class="alert alert-success">Import Data Done</div>';
}
}
else
{
$output = '<div class="alert alert-warning">Invalid File</div>';
}
}
else
{
$output = '<div class="alert alert-warning">Please Select XML File</div>';
}
echo $output;
?>
You should be able to do it using variable variables, so first assign Con-1 to a variable and then substitute this variable for the name in the assignment...
$var = 'Con-1';
$statement->execute(
array(
':name' => $data->$var[$i]->name,
':address' => $data->$var[$i]->address,
':gender' => $data->$var[$i]->gender,
':designation' => $data->$var[$i]->designation,
':age' => $data->$var[$i]->age
)
);