PHP - 在带有函数的IF语句中使用OR

Question

I am using OR in if statement While adding OR its not working. Follow the code :

if(!exists('vouchers','v_id',$generate_id) OR !exists('vouchers','hash',$generate_hash))
{
     //Doing something
}

But when I do only one function call its workes.

if(!exists('vouchers','v_id',$generate_id)){//WORK...}

exists function :

function exists($table,$where,$value){
global $db;
$query = $db->query('SELECT * FROM '.$table.' WHERE '.$where.'='.$value.'');
if($query->num_rows == 0) {
    return false;
}else{
    return true;
}

}

Any helps to fix my code ?

Answer 1

You need to use the logical AND operator if you want to check the both like :

if(!exists('vouchers','v_id',$generate_id) AND !exists('vouchers','hash',$generate_hash)){
___________________________________________^^^

Else using the OR operator, the code inside condition will be reached if just one of the condition is true.