用C语言写时间间隔（多实例测试）问题

Question

运用函数方式解决时间间隔（多实例测试）问题 只用C语言写 以及主函数与子函数直接的关系 子函数如何返回数值

Answer 1

#include <iostream>
#include <iomanip> 

using namespace std;

int HmsToS(int h, int m, int s) {
    return h * 3600 + m * 60 + s;
}

void PrintTime(int s) {
    int hours = s / 3600;
    s %= 3600;
    int minutes = s / 60;
    int seconds = s % 60;

    cout << setw(2) << setfill('0') << hours << ":"
         << setw(2) << setfill('0') << minutes << ":"
         << setw(2) << setfill('0') << seconds << endl;
}

int main() {
    string time1, time2;
    int h1, m1, s1, h2, m2, s2;

    while (cin >> time1 >> time2) {
        // 解析时间点1
        h1 = stoi(time1.substr(0, 2));
        m1 = stoi(time1.substr(3, 2));
        s1 = stoi(time1.substr(6, 2));

        // 解析时间点2
        h2 = stoi(time2.substr(0, 2));
        m2 = stoi(time2.substr(3, 2));
        s2 = stoi(time2.substr(6, 2));

        // 计算时间差
        int totalSeconds1 = HmsToS(h1, m1, s1);
        int totalSeconds2 = HmsToS(h2, m2, s2);
        int diffSeconds = totalSeconds2 - totalSeconds1;
        PrintTime(diffSeconds);
    }
    return 0;
}