登录代码出错了

Question

I am having problem logging in, below is a login code. When I submit login info it says Incorrect Information, I have gone wrong somewhere in code and can't figure it out. I have used password_hash() function, checked my database and it works well. Surely somethings wrong with login code. Now I tried echoing $pass_db and on submitting info I see the password is echoed correctly but incorrect information is also displayed and I am not redirected to main.php as I should be.

login.php

<?php
if(isset($_POST['login'])){ 
$username = $_POST['user_login'];
$password = $_POST['password_login'];

$stmt = $db->prepare("SELECT * FROM userss WHERE username = :username AND password = :password");
$stmt->execute(array(':username'=>$username,':password'=>$password));
$row = $stmt->fetch(PDO::FETCH_ASSOC);

$user_db = $row['username'];
$pass_db = $row['password'];

if(password_verify($password, $pass_db))  {  
$_SESSION['username']=$username;
if (isset($_POST['rememberme'])) {
  setcookie('username', $username,time()[phone]);
 }
   header("Location:main.php");

 }
 else {
 echo "Incorrect Information!";
 }
 }
 ?>

register code

$pswd = password_hash($pswd, PASSWORD_DEFAULT);
$pswd2 = password_hash($pswd2, PASSWORD_DEFAULT);
$stmt = $db->prepare("INSERT INTO userss (username,first_name,last_name,email,password,password2) VALUES (:username,:first_name,:last_name,:email,:password,:password2,)");  
$stmt->execute( array(':username'=>$un,':first_name'=>$fn,':last_name'=>$ln,':email'=>$em,':password'=>$pswd,':password2'=>$pswd2));

if ($stmt->rowCount() == 1) {
header("Location: login.php");
} 
else {
echo "error";
}