Linux PHP ExtractTo返回整个路径而不是文件结构

Question

I am pulling my hair out over here. I have spent the last week trying to figure out why the ZipArchive extractTo method behaves differently on linux than on our test server (WAMP).

Below is the most basic example of the problem. I simply need to extract a zip that has the following structure:

my-zip-file.zip
-username01
    --filename01.txt
    -images.zip
        --image01.png
    -songs.zip
        --song01.wav
-username02
    --filename01.txt
    -images.zip
       --image01.png
    -songs.zip
       --song01.wav

The following code will extract the root zip file and keep the structure on my WAMP server. I do not need to worry about extracting the subfolders yet.

<?php
if(isset($_FILES["zip_file"]["name"])) {
$filename = $_FILES["zip_file"]["name"];
$source = $_FILES["zip_file"]["tmp_name"];
$errors = array();  

$name = explode(".", $filename);

$continue = strtolower($name[1]) == 'zip' ? true : false;
if(!$continue) {
    $errors[] = "The file you are trying to upload is not a .zip file. Please try again.";
}

$zip = new ZipArchive();

if($zip->open($source) === FALSE)
{
    $errors[]= "Failed to open zip file.";
}

if(empty($errors))
{
    $zip->extractTo("./uploads");
    $zip->close();
    $errors[] = "Zip file successfully extracted! <br />";
}

}
?>

The output from the script above on WAMP extracts it correctly (keeping the file structure).

When I run this on our live server the output looks like this:

--username01\filename01.txt
--username01\images.zip
--username01\songs.zip
--username02\filename01.txt
--username02\images.zip
--username02\songs.zip

I cannot figure out why it behaves differently on the live server. Any help will be GREATLY appreciated!

Answer 1

To fix the file paths you can iterate over all extracted files and move them.

Supposing inside your loop over all extracted files you have a variable $source containing the file path (e.g. username01\filename01.txt) you can do the following:

// Get a string with the correct file path
$target = str_replace('\\', '/', $source);

// Create the directory structure to hold the new file
$dir = dirname($target);
if (!is_dir($dir)) {
    mkdir($dir, 0777, true);
}

// Move the file to the correct path.
rename($source, $target);

Edit

You should check for a backslash in the file name before executing the logic above. With the iterator, your code should look something like this:

// Assuming the same directory in your code sample.
$dir = new DirectoryIterator('./uploads');
foreach ($dir as $fileinfo) {
    if (
        $fileinfo->isFile() 
        && strpos($fileinfo->getFilename(), '\\') !== false // Checking for a backslash
    ) {
        $source = $fileinfo->getPathname();

        // Do the magic, A.K.A. paste the code above

    }
}