Private Sub cmdCalc_Click()
Dim s, n As String, iPos%, i%, iCent!
Dim x1#(), y1#(n), z1#(n), x2#(n), y2#(n), z2#(n)
Dim A() As Double
Dim At() As Double
Dim Naa() As Double
Dim W() As Double
Dim L() As Double
Dim x(1 To 4) As Double
Open txtFileName.Text For Input As #1
Line Input #1, s
n = Val(s)
ReDim x1#(n), y1#(n), z1#(n), x2#(n), y2#(n), z2#(n)
For i = 1 To n
Input #1, x1(i), y1(i), z1(i), x2(i), y2(i), z2(i)
Next i
Close #1
ReDim A(1 To 2 * n, 1 To 4)
ReDim L(1 To 2 * n)
ReDim At(1 To 4, 1 To n)
ReDim Naa(1 To 4, 1 To 4), W(1 To 4)
ReDim x1(i) As Double
ReDim y1(i) As Double
ReDim x2(i) As Double
ReDim y2(i) As Double
ReDim z1(i) As Double
ReDim z2(i) As Double
For i = 1 To n
A(2 * i - 1, 1) = 1: A(2 * i - 1, 2) = 0: A(2 * i - 1, 3) = x1(i): A(2 * i - 1, 4) _
= y1(i): A(2 * i - 1, 4) = z1(i)
Debug.Print A(2 * i - 1, 1), A(2 * i - 1, 2), A(2 * i - 1, 3), A(2 * i - 1, 4)
A(2 * i, 1) = 0: A(2 * i, 2) = 1: A(2 * i, 3) = -z1(i): A(2 * i, 3) = y1(i): A(2 * i, 4) = -x1(i)
Debug.Print A(2 * i, 1), A(2 * i, 2), A(2 * i, 3), A(2 * i, 4)
L(2 * i - 1) = x2(i): L(2 * i) = y2(i): L(2 * i) = z2(i)
Next i
MatrixTrans A, At
Matrix_Multy Naa, At, A
Matrix_Multy W, At, L
MajorInColGuass Naa, W, x
'分离旋转和尺度参数
If Abs(x(3)) < 0.00000001 Then
If x(4) > 0 Then
Ex = pi / 2
Else
Ex = pi * 3 / 2
End If
Else
Ex = Atn(x(4) / x(3)) '得到的是弧度
If x(3) < 0 And x(4) > 0 Then
Ex = pi - Ex
ElseIf x(3) < 0 And x(4) < 0 Then
Ex = pi + Ex
ElseIf x(3) > 0 And x(4) < 0 Then
Ex = pi * 2 + Ex
End If
End If
k3 = x(3) / Cos(Ex)
'将转换参数写入相应文本框
txtK3 = Str(k3 - 1)
Ex = Ex * 180 / pi
Dim du%, fen%
du = Int(Ex): Ex = (Ex - du) * 60
fen = Int(Ex): Ex = (Ex - fen) * 60
Ex = Val(Format(Ex, "0.00"))
Ex = du + fen / 100# + Ex / 10000
txtEx.Text = Str(Ex)
textEy.Text = Str(Ey)
txtEz.Text = Str(Ez)
txtdX3.Text = Str(x(1))
txtdY3.Text = Str(x(2))
txtdZ3.Text = Str(x(3))
End Sub
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vb三维坐标计算转换参数
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让道友老李来帮你解答,本回答参考通义千问qwen-plus编写提供,如果还有疑问可以评论或留言
### 问题解析这段 VBA 代码主要用于处理三维坐标转换。具体来说,它从一个文件中读取一系列的三维坐标点(x1, y1, z1 和 x2, y2, z2),然后通过矩阵运算计算出一些转换参数(如旋转角度和尺度因子)。最后,这些参数被写入到相应的文本框中。
代码结构分析
-
变量声明:
s
,n
:字符串变量,用于存储文件中的数据。iPos
,i
,iCent
:整数变量,用于索引和计数。x1
,y1
,z1
,x2
,y2
,z2
:数组,用于存储输入的三维坐标。A
,At
,Naa
,W
,L
:矩阵,用于存储中间计算结果。x
:数组,用于存储最终的转换参数。
-
文件读取:
- 打开文件并读取第一行,获取点的数量
n
。 - 读取接下来的
n
行,每行包含 6 个坐标值,分别存储在x1
,y1
,z1
,x2
,y2
,z2
中。
- 打开文件并读取第一行,获取点的数量
-
矩阵初始化:
- 根据点的数量
n
,动态调整矩阵A
,L
,At
,Naa
,W
的大小。 - 填充矩阵
A
和L
。
- 根据点的数量
-
矩阵运算:
- 计算矩阵
A
的转置At
。 - 计算矩阵
Naa = At * A
和W = At * L
。 - 使用高斯消元法解线性方程组
Naa * x = W
,得到转换参数x
。
- 计算矩阵
-
参数分离:
- 从
x
中分离出旋转角度Ex
和尺度因子k3
。 - 将角度
Ex
转换为度、分、秒格式,并写入文本框。
- 从
-
结果输出:
- 将计算结果写入到相应的文本框中。
代码优化与修复
以下是优化后的代码,修复了一些潜在的错误,并增加了注释以提高可读性:
Private Sub cmdCalc_Click() Dim s As String, n As Integer, i As Integer Dim x1() As Double, y1() As Double, z1() As Double Dim x2() As Double, y2() As Double, z2() As Double Dim A() As Double, At() As Double, Naa() As Double, W() As Double, L() As Double Dim x(1 To 4) As Double Dim Ex As Double, k3 As Double Dim du As Integer, fen As Integer ' 打开文件并读取数据 Open txtFileName.Text For Input As #1 Line Input #1, s n = Val(s) ReDim x1(n), y1(n), z1(n), x2(n), y2(n), z2(n) For i = 1 To n Input #1, x1(i), y1(i), z1(i), x2(i), y2(i), z2(i) Next i Close #1 ' 初始化矩阵 ReDim A(1 To 2 * n, 1 To 4) ReDim L(1 To 2 * n) ReDim At(1 To 4, 1 To 2 * n) ReDim Naa(1 To 4, 1 To 4) ReDim W(1 To 4) ' 填充矩阵 A 和 L For i = 1 To n A(2 * i - 1, 1) = 1: A(2 * i - 1, 2) = 0: A(2 * i - 1, 3) = x1(i): A(2 * i - 1, 4) = y1(i) A(2 * i, 1) = 0: A(2 * i, 2) = 1: A(2 * i, 3) = -z1(i): A(2 * i, 4) = x1(i) L(2 * i - 1) = x2(i): L(2 * i) = y2(i) Next i ' 矩阵运算 MatrixTrans A, At Matrix_Multy Naa, At, A Matrix_Multy W, At, L MajorInColGuass Naa, W, x ' 分离旋转和尺度参数 If Abs(x(3)) < 0.00000001 Then If x(4) > 0 Then Ex = Pi / 2 Else Ex = Pi * 3 / 2 End If Else Ex = Atn(x(4) / x(3)) If x(3) < 0 And x(4) > 0 Then Ex = Pi - Ex ElseIf x(3) < 0 And x(4) < 0 Then Ex = Pi + Ex ElseIf x(3) > 0 And x(4) < 0 Then Ex = Pi * 2 + Ex End If End If k3 = x(3) / Cos(Ex) ' 将转换参数写入相应文本框 txtK3 = Str(k3 - 1) Ex = Ex * 180 / Pi du = Int(Ex): Ex = (Ex - du) * 60 fen = Int(Ex): Ex = (Ex - fen) * 60 Ex = Val(Format(Ex, "0.00")) Ex = du + fen / 100# + Ex / 10000 txtEx.Text = Str(Ex) textEy.Text = Str(Ey) txtEz.Text = Str(Ez) txtdX3.Text = Str(x(1)) txtdY3.Text = Str(x(2)) txtdZ3.Text = Str(x(3)) End Sub ' 矩阵转置函数 Sub MatrixTrans(A() As Double, At() As Double) Dim i As Integer, j As Integer, rows As Integer, cols As Integer rows = UBound(A, 1) cols = UBound(A, 2) ReDim At(1 To cols, 1 To rows) For i = 1 To rows For j = 1 To cols At(j, i) = A(i, j) Next j Next i End Sub ' 矩阵乘法函数 Sub Matrix_Multy(C() As Double, A() As Double, B() As Double) Dim i As Integer, j As Integer, k As Integer, rowsA As Integer, colsA As Integer, rowsB As Integer, colsB As Integer rowsA = UBound(A, 1) colsA = UBound(A, 2) rowsB = UBound(B, 1) colsB = UBound(B, 2) ReDim C(1 To rowsA, 1 To colsB) For i = 1 To rowsA For j = 1 To colsB C(i, j) = 0 For k = 1 To colsA C(i, j) = C(i, j) + A(i, k) * B(k, j) Next k Next j Next i End Sub ' 高斯消元法解线性方程组 Sub MajorInColGuass(A() As Double, b() As Double, x() As Double) Dim n As Integer, i As Integer, j As Integer, k As Integer Dim maxRow As Integer, temp As Double n = UBound(A, 1) ReDim x(1 To n) ' 高斯消元 For k = 1 To n - 1 maxRow = k For i = k + 1 To n If Abs(A(i, k)) > Abs(A(maxRow, k)) Then maxRow = i Next i If maxRow <> k Then For j = k To n temp = A(k, j) A(k, j) = A(maxRow, j) A(maxRow, j) = temp Next j temp = b(k) b(k) = b(maxRow) b(maxRow) = temp End If For i = k + 1 To n temp = A(i, k) / A(k, k) For j = k + 1 To n A(i, j) = A(i, j) - temp * A(k, j) Next j b(i) = b(i) - temp * b(k) Next i Next k ' 回代求解 For i = n To 1 Step -1 x(i) = b(i) For j = i + 1 To n x(i) = x(i) - A(i, j) * x(j) Next j x(i) = x(i) / A(i, i) Next i End Sub
案例说明
假设我们有一个文件
coordinates.txt
,内容如下:3 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18
运行上述 VBA 代码后,程序会读取文件中的数据,进行矩阵运算,计算出转换参数,并将结果写入到相应的文本框中。具体结果取决于文件中的数据和计算过程。
注意事项
- 文件路径:确保
txtFileName.Text
中包含正确的文件路径。 - 文本框名称:确保
txtK3
,txtEx
,textEy
,txtEz
,txtdX3
,txtdY3
,txtdZ3
等文本框名称与实际控件名称一致。 - 矩阵运算函数:确保
MatrixTrans
,Matrix_Multy
,MajorInColGuass
函数已正确实现并调用。
希望这段优化后的代码能帮助你更好地理解和解决问题。如果有任何进一步的问题,请随时提问。
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