douzhang3822
2015-04-03 09:11
浏览 55
已采纳

jQuery Tokeninput插件PHP没有json的结果

I try to use the JQuery Tokeninput. While I introduce on the search fields the text , it doesn't show anything. It stays on searching forever...

From the documentation I see that the format of the resunt of json_encode should looks like :

[{"id":"856","name":"House"},
{"id":"1035","name":"Desperate Housewives"},
...]

but when I access my json localhost/json.php?q=house returns datas like :

["house1","house2" ...] 

so it doesn't contains the "{}" .

I'm sure that the paths to the js,and css are ok. the script is here:

<script type="text/javascript">
                    $(document).ready(function () {
                        $("#textarea").tokenInput('link/json.php');
                    });
                </script>

The json code looks like :

$rows = array();
$q=$_GET['q']; 

$query_get_element = "SELECT DISTINCT `column` FROM `table` WHERE `column` LIKE '%".$q."%'";
$query_get_element = mysql_query($query_get_element);
$row_cen = mysql_fetch_array($query_get_element);

$json=array();

while ($row2 = mysql_fetch_array($query_get_element))
    array_push($json, $row2['column']);

echo json_encode($json);

While I search the console shows localhost/json.php?q=house Any advice to solve this ? Thanks in advance!

on console (google chrome I see:

GET http://localhost/json.php?q=house 404 (Not Found)

图片转代码服务由CSDN问答提供 功能建议

我尝试使用JQuery Tokeninput。 虽然我在搜索字段中介绍了文本,但它没有显示任何内容。 它一直在寻找... ...

从文档中我看到json_encode的resunt格式应如下所示:

   [{“id”:“856”,“name”:“House”},
 {“id”:“1035”,“name”:“绝望的主妇”},
 ...] 
   
 
 

但是当我访问我的json localhost / json.php时?q = house返回如下数据:

  [“house1”  ,“house2”...] 
   
 
 

因此它不包含“{}”。

我确定js和css的路径都可以。 脚本在这里:

 &lt; script type =“text / javascript”&gt; 
 $(document).ready(function(){
 $(“#  textarea“)。tokenInput('link / json.php'); 
}); 
&lt; / script&gt; 
   
 
 

json代码如下所示:

  $ rows = array(); 
 $ q = $ _ GET ['q'];  
 
 $ query_get_element =“SELECT DISTINCT`column` FROM`table` WHERE`point` LIKE'%”。$ q。“%'”; 
 $ query_get_element = mysql_query($ query_get_element); 
 $ row_cen =  mysql_fetch_array($ query_get_element); 
 
 $ json = array(); 
 
while($ row2 = mysql_fetch_array($ query_get_element))
 array_push($ json,$ row2 ['column']); 
 \  necho json_encode($ json); 
   
 
 

我搜索控制台时显示localhost / json.php?q = house 任何建议来解决这个问题? 提前致谢!

在控制台上(google chrome我看到了:

  GET http://localhost/json.php?q = 房子404(未找到)
   
 
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1条回答 默认 最新

  • douyoufan7881 2015-04-03 10:40
    已采纳

    I solved the issue. The problem was in my JSON . It was : array_push($json, array($row2['column'])); the pluggin search for the name of column and the array of column so it need to be like :

    array_push($json, array("column" => $row2['column']));

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