在非对象上调用成员函数bindValue（）[duplicate]

Question

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• My PDO Statement doesn't work 1 answer

So I'm trying to create a prepared insert statement to a database for a web app. For the registration system, I'm feeding in values using post, then redirecting to a webpage to do the processing. However, I keep getting the error 'Call to a member function bindValue() on a non-object in /path/to/file.php on line 18, the first reference to bindValue(). The code is:

<?php

 session_start();

 require "database.php";
 $db = new Database("bills.db");

 $admin_password = $_POST['admin_password'];
 $admin_email = $_POST['admin'];
 $salt = sha1(time());
 $group_name = $_POST['group_name'];
 $group_password = $_POST['password'];

 $admin_hash = sha1($salt."--".$admin_password);
 $group_hash = sha1($salt."--".$group_password);

$stmt = $db->prepare("INSERT INTO billgroup VALUES (NULL, :adminemail, :adminpassword_hash, :groupname, :password_hash, :salt)");
$stmt->bindValue(':adminemail', $admin_email, SQLITE3_TEXT);
$stmt->bindValue(':adminpassword_hash', $admin_hash, SQLITE3_TEXT);
$stmt->bindValue(':groupname', $group_name, SQLITE3_TEXT);
$stmt->bindValue(':password_hash', $group_hash, SQLITE3_TEXT);
$stmt->bindValue(':salt', $salt, SQLITE3_TEXT);
$results = $stmt->execute();




 $stmt = $db->prepare("SELECT * FROM billgroup WHERE adminemail = :adminemail");
 $stmt->bindValue(':adminemail', $admin_email, SQLITE3_TEXT);
 $users = $stmt->execute();
 $user = $users->fetchArray();
...

</div>

Answer 1

You want connect to a sqlite database but you have:

$db = new Database("bills.db");

You must know that you must have something like this:

$db = new PDO('sqlite:bills.db');

And change in all the bindValue calls the SQLITE3_TEXT to PDO::PARAM_STR like this:

$stmt->bindValue(':adminemail', $admin_email, SQLITE3_TEXT);

to:

$stmt->bindValue(':adminemail', $admin_email, PDO::PARAM_STR);