PHP数据库DATE与今天的DATE相比

Question

In the database, I Have DOB table wich is DATE . so I have problem in search function, because I want to search people by Date to be correct age at any time. So fields in search is AGE for example 18-25 , . I want to make searchage1 = 18 in this example and searchage2 = 25.

 `dob BETWEEN ".$search_data['searchage1']." AND ".$search_data['searchage2'];`

I want to convert this 18 and 25 into DATE then Compare it to Database DATES . I have tried some possiblity with no sucess, any idea?

Answer 1

Firstly, you need to calculate the age based form the dob field, then use this in your WHERE statements.

Please see these threads on how to calculate age in SQL: here or here

EG:

SELECT *, DATEDIFF(dob, '2016-06-28')/365.25 AS `age` WHERE `age` >= '18' AND `age` =< '25';

or

SELECT *, YEAR(CURRENT_TIMESTAMP) - YEAR(dob) - (RIGHT(CURRENT_TIMESTAMP, 5) < RIGHT(dob, 5)) AS `age` WHERE `age` >= '18' AND `age` =< '25';