songyanyan55 于 2013.06.06 11:49 提问
- Oracle中varchar2类型的id为自动增长
-
Oracle中id的类型为varchar2(10)主键,怎样创建自动增长的id
-
-
u014530814
2014.08.27 20:15
可以的,使用序列
创建序列
create sequence SEQ_CEID
minvalue 1
maxvalue 9999999999
start with 41
increment by 1
cache 20;
创建表,插入,查询
create table table_f (
id varchar(10) primary key,
name varchar(20)
)
insert into table_f values(SEQ_CEID.NEXTVAL,'wef')
或者加上触发器
2.--创建表
3.create table book(
- bookId varchar2(4) primary key,
- name varchar2(20)
6.);
7.--创建序列
8.create sequence book_seq start with 1 increment by 1;
-
10.--创建触发器
11.create or replace trigger book_trigger
12.before insert on book
13.for each row
14.begin
15.select book_seq.nextval into :new.bookId from dual;
16.end ;
17.--添加数据
18.insert into book(name) values ('cc');
19.insert into book(name) values ('dd');
准确详细的回答,更有利于被提问者采纳,从而获得C币。复制、灌水、广告等回答会被删除,是时候展现真正的技术了!