I'm building a php script to transfer selected contents of an xml file to an sql database..
One of the hardcoded XML contents is formatted like this:
<visualURL>
id=18144083|img=http://upload.wikimedia.org/wikipedia/en/8/86/Holyrollernovacaine.jpg
</visualURL>
And I'm looking for a way to just get the contents of the URL (all text after img=).
$Image = $xpath->query("substring-after(/Playlist/PlaylistEntry[1]/visualURL[1]/text(), 'img=')", $element)->item(0)->nodeValue;
Displays a property non-object error on my php output.
There must be another way to just extract the URL contents using XPath that I want, no?
Any help would be greatly appreciated!
EDIT:
Here is the minimum code
<?php
$xmlDoc = new DOMDocument();
$xmlDoc->loadXML('<Playlist>
<PlaylistEntry>
<visualURL>
id=12582194|img=http://upload.wikimedia.org/wikipedia/en/9/96/Sometime_around_midnight.jpg
</visualURL>
</PlaylistEntry>
</Playlist>');
$xpath = new DOMXpath($xmlDoc);
$elements = $xpath->query("/Playlist/PlaylistEntry[1]");
if (!is_null($elements))
foreach ($elements as $element)
$Image = $xpath->query("substring-after(/Playlist/PlaylistEntry[1]/visualURL[1]/text(), 'img=')", $element)- >item(0)->nodeValue;
print "Finished Item: $Image";
?>
EDIT 2:
After some research I believe I must use $xpath->evaluate instead of my current use of $xpath->query
see this link Same XPath query is working with Google docs but not PHP
I'm not exactly sure how to do this yet.. but i will investigate more in the morning. Again, any help would be appreciated.