dongtuan1594 2015-03-09 08:35
浏览 18
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php-auto加载选定的下拉值

i have a drop down menu..i want to auto load selected value when page is open.but i do not know how to do it.anyone can help?

<select name="num" onchange="this.form.submit()">

        <option value="25" selected>25</option>
        <option value="50">50</option>
        <option value="75">75</option>
        <option value="100">100</option>
    </select>

for example, when i go to that page, the page auto display 25 record to me.

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1条回答 默认 最新

  • doujing1858 2015-03-09 08:42
    关注

    Your page must be named with .php extension and you have to have access to that result:

        <?php
        //let's assume you take selected value from $_POST
        if(isset($_POST['num']){
            $selected_option = $_POST['num'];
        }else{
            $selected_option = '';
        }
    
        $options = array(25,50,75,100);
        ?>
        <form id="myForm" method="post" action = "">
        <select name="num" onchange="document.getElementById('myForm').submit()">
        <?php
        foreach($options as $v){
            if($v == $selected_option){
                $selected = 'selected = "selected"';
            }else{
                $selected = '';
            }
            echo "<option value='$v' $selected>$v</option>";
        }
        ?>    
        </select>
        </form>
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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