I have a project and have run into a problem. I use Codeigniter HMVC and therefore build modules. I appreciate your help. Thanks.
I have two module methods where one calls another. The other delivers a database result and loads it into a view that is then passed on to the template from the 1st module method. I now realize, that since I get a view and not data from the 2nd module, I don't see how I can check if there is a database record returned, and I don't want another database call just for that purpose. The seperation between "item" and "description" modules is required. Having data sent instead would make a really messy structure that to my understanding would counteract the HMVC structure. I therefore need to keep this structure. How can I check if database record exists and only run the 1st method if it does? Please advise. Thanks
1st module (controller method) called through URL
function view_item($item_id)
{
$data['item_id'] = $item_id;
$data['item'] = $this->item;
$data['item_group'] = $this->item_group;
$data['content_module'] = Modules::run("descriptions/view",$item_id);
$data['active_menu_item'] = "descriptions";
$data['view_file'] = "handle_view";
$data['module'] = $this->module;
$template = "application";
$this->load->module('templates');
$this->load->templates->$template($data);
}
2nd module method called by 1st module method
function view($item_id)
{
$data['title'] = "View description";
$data['page_title'] = "View description";
$data['page_subtitle'] = "This item";
$data['item_id'] = $item_id;
$array = array('item_id'=> $item_id,'group_id'=> $this->group_id);
$object = $this->get_where_custom($array);
$num_rows = $object->num_rows;
$descriptions = $object->result();
$data['description'] = $descriptions[0];
$this->load->view('view_view',$data);
}
