如开始时间为5:00,结束时间为24:00,将传过来的数组
timeArray:['6:05','6:15','6:20','6:25','6:40','6:45','6:55','7:00','8:00','9:00'],
inStation:[10,20,50,60,40,70,50,80,20,10],
outStation:[30,40,35,65,0,40,20,30,10,20]
补成timeArray:
['5:00','5:05','5:10',5:15'',····'6:05','6:10',6:15','6:20','6:25','6:30','6:35',6:40','6:45','6:50','6:55','7:00','7:05',········'8:00',········'24:00'],
inStation:[0,0,········10,0,20,50,60,40,70,50,80,20,10],
outStation:[0,0,········30,40,35,65,0,40,20,30,10,20]
多出的时间间隔将数值补0

如何用js将数组中的数据补全
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3条回答 默认 最新
- renkai721 2019-09-27 17:11关注
下面给你一段JS,你自己看看
function printTime() { // 不知道你timeArray需要干什么 // var timeArray = new Array('6:05','6:15','6:20','6:25','6:40','6:45','6:55','7:00','8:00','9:00'); var time = ""; for (var i = 5; i <= 23; i++) { for (var j = 0; j < 12; j++) { var min = ""; if (j <= 1) { min = "0"; } time = i + ":" + min + (j * 5); console.log(time); } } time = "24:00"; console.log(time); }
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