dosf40815 2013-11-27 16:38 采纳率: 100%
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php用正则表达式获取css

I'm trying to get css selector + styles with a regexp but there is always a problem...

So do you have an idea (exemple ?) of a regexp do get this:

array(
[0] => "div {
    background: red;
    color: blue;
}",
[1] => "section {
    /* comment with bad idea } <- this break regexp [^}]+ */
    background: blue;
    color: red;
}"
);

fom this css:

div {
    background: red;
    color: blue;
}

section {
    /* comment with bad idea } <- this break regexp [^}]+ */
    background: blue;
    color: red;
}

Thx

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  • duan0427 2013-12-06 23:11
    关注

    I finally did it by another way. First, I start by quoting the undesired symbols with these regex

    string = string
    .replace(/(')([^']*)(')/ig, function(found){
    
        return found.replace(/([\[\]\s\,\#\.\:\>\~])/ig, "\/\/$1\\\\");
    
    })
    .replace(/(\")([^\"]*)(\")/ig, function(found){
    
        return found.replace(/([\[\]\s\,\#\.\:\>\~])/ig, "\/\/$1\\\\");
    
    });
    

    Then, I split the string with another regexp:

    string = string.split(/(?!\/\/)([\s\>\,])(?!\\\\)|(?=(?!\/\/)[\#\.\[\:](?!\\\\))/ig);
    

    And, to finish, if( string[x].match(/^[a-z]+$/ig) ){..}; it is a tagName

    If you see something bad, I'm listening to you.

    Edit :

    Oups ! I forgot my answer was about php, sorry. But I apply the same method for php, except lookBefore simplify and reduce the regexp to only one, then split...

    J

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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