duanouyong4228 2013-05-25 10:13
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在PHP分页中使用COUNT和Distinct

HI I have a PHP Pagination system, what i am trying to do is use Distinct to return only unique values, what happens is the page shows how many pages there should be but doesn't give me any results.

My code is here

$query = "SELECT DISTINCT ip_address, 
                 COUNT(*) as num 
          FROM $tableName  
          WHERE hostname 
          LIKE 'mail%' AND type='6'";
$total_pages = mysql_fetch_array(mysql_query($query));
$total_pages = $total_pages[num];

$stages = 3;
$page = mysql_escape_string($_GET['page']);

if($page){
    $start = ($page - 1) * $limit; 
}else{
    $start = 0; 
}   

// Get page data
$query1 = "SELECT DISTINCT ip_address, 
                  hostname 
            FROM masterip_details  
                WHERE hostname 
            LIKE 'mail%' AND type='6' 
                LIMIT $start, $limit";
$result = mysql_query($query1);
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2条回答 默认 最新

  • douche1936 2013-05-25 10:28
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    If you don't have an index on the ip_address field, I'd just use SELECT COUNT(DISTINCT ip_address) as num. If you have an index, you could just as well do this:

    SELECT COUNT(type) AS num FROM tbl WHERE hostname LIKE 'mail%' and type = 6 GROUP BY ip_address;
    

    Because, if you're grouping on an index, DISTINCT is equivalent to GROUP BY. More details here and here.

    The real reason for my answering this question though: Please, don't use the deprecated mysql_* extension. Use either one of the replacements, mysqli_*, with i for improved, or PDO, which seems to be more commonly used.

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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