douqiong8412 2010-06-02 21:19
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如何在while循环中只显示一次

I've got a mysql query running and it checks to see if an iterator is equal to 1, then display this div title...

if ($this->dliterator == 1) {echo "<div class='clientsection' id='downloads'>Downloads</div><br/>";};

The problem is, is that the dl iterator may not necessarily start at 1. (it is directly related to a downloadid from the database).

How can I get this to display only for the first time through the loop ONLY?

while ($row = mysql_fetch_assoc($result)) { 

   if ($row['download'] != null){
    if ($this->dliterator == 1) {echo "<div class='clientsection' id='downloads'>Downloads</div><br/>";};


    if ($editDownload == 1) {
     echo "<div class='clientlink' style='margin-top: 15px;'>";
     echo "<input name='downloads[$this->dliterator][name]' type='text' id='download$this->dliterator' value='" . $row['download'] . "'/>";
     echo "<input name='downloads[$this->dliterator][title]' type='text' id='downloadtitle$this->dliterator' value='" . $row['downloadtitle'] . "'/>";
     echo "<img class='removelink' src='/images/deletelink.png' width='15' />";
     echo "<input id='downloadid' name='downloads[$this->dliterator][id]' type='hidden' value='".$row['downloadid']."' style='display: none'/>";
     echo "<br/><img id='uploaddownload$uploaditerator' class='uploaddownload' src='../images/upload.png' width='80'/>"; 
     echo "</div>";


    };

   };

   $this->dliterator++;

   $uploaditerator++;
};

Thanks for all the answers! Here's my working solution thanks to Zuul:

if ($row['download'] != null){
if (($this->dliterator != null ) && ($check ==0)) {echo "<div class='clientsection' id='downloads'>Downloads</div><br/>";
$check++;};
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4条回答 默认 最新

  • doufang1954 2010-06-02 21:24
    关注

    Try this:

    $check=0;
    
    if (($this->dliterator == 1) && ($check==0)) {
      echo "<div class='clientsection' id='downloads'>Downloads</div><br/>";
      $check++;
    };
    

    It will enter the if statement if your dliterator==1 and if $check hasn't change... After inside, it will change the $check thus preventing the if statement to run again!

    Hope it helps!

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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