两个八位字符串,前三位和后五位互换或者前两位和后六位互换得到两个新的字符串。
1条回答 默认 最新
- threenewbee 2019-09-28 16:23关注
s1 = "12345678" s1 = s1[3:8] + s1[0:3] print(s1) s2 = "abcdefgh" s2 = s2[2:8] + s2[0:2] print(s2)
45678123
cdefghab本回答被题主选为最佳回答 , 对您是否有帮助呢?解决 3无用 2
s1 = "12345678"
s1 = s1[3:8] + s1[0:3]
print(s1)
s2 = "abcdefgh"
s2 = s2[2:8] + s2[0:2]
print(s2)
45678123
cdefghab