file_get_contents无法使用有效网址打开流

Question

I'm trying to use this code in a php file. I want get the source code from this url and parse the content.

<?php 
  $fuente = file_get_contents('http://www.akiracomics.com');
  echo $fuente;
?>

The problem is, after execute the code I received this error

Warning: file_get_contents(http://www.akiracomics.com) [function.file-get-contents]: failed to open stream: Connection timed out in XXXXXX/test.php on line 2

I tried from the same server to other url and works perfect.

Any idea?

Thanx

Answer 1

I finally found the solution. I need to use a curl_exec instead file_get_contents. With this code, everything works fine.

            $curlIMG = curl_init();
            curl_setopt($curlIMG, CURLOPT_URL, "http://www.google.es");
            curl_setopt($curlIMG, CURLOPT_RETURNTRANSFER, true);
            curl_setopt($curlIMG, CURLOPT_HEADER, false);
            $imgBinary = curl_exec($curlIMG);
            curl_close($curlIMG);